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phosphorus pentabromide

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phosphorus pentabromide
phosphorus pentabromide

Chemical names and formulas

formula | PBr_5 Hill formula | Br_5P name | phosphorus pentabromide IUPAC name | pentabromophosphorane alternate names | pentabromophosphorane | phosphorane, pentabromo | phosphorane, pentabromo- | phosphoric bromide | phosphorous pentabromide | phosphorus(V) bromide mass fractions | Br (bromine) 92.8% | P (phosphorus) 7.19%
formula | PBr_5 Hill formula | Br_5P name | phosphorus pentabromide IUPAC name | pentabromophosphorane alternate names | pentabromophosphorane | phosphorane, pentabromo | phosphorane, pentabromo- | phosphoric bromide | phosphorous pentabromide | phosphorus(V) bromide mass fractions | Br (bromine) 92.8% | P (phosphorus) 7.19%

Lewis structure

Draw the Lewis structure of phosphorus pentabromide. Start by drawing the overall structure of the molecule:  Count the total valence electrons of the bromine (n_Br, val = 7) and phosphorus (n_P, val = 5) atoms: 5 n_Br, val + n_P, val = 40 Calculate the number of electrons needed to completely fill the valence shells for bromine (n_Br, full = 8) and phosphorus (n_P, full = 8): 5 n_Br, full + n_P, full = 48 Subtracting these two numbers shows that 48 - 40 = 8 bonding electrons are needed, which are already accounted for in the structure. Note that the valence shell of phosphorus has been expanded to 5 bonds. After accounting for the expanded valence, there are 5 bonds and hence 10 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 40 - 10 = 30 electrons left to draw: Answer: |   |
Draw the Lewis structure of phosphorus pentabromide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the bromine (n_Br, val = 7) and phosphorus (n_P, val = 5) atoms: 5 n_Br, val + n_P, val = 40 Calculate the number of electrons needed to completely fill the valence shells for bromine (n_Br, full = 8) and phosphorus (n_P, full = 8): 5 n_Br, full + n_P, full = 48 Subtracting these two numbers shows that 48 - 40 = 8 bonding electrons are needed, which are already accounted for in the structure. Note that the valence shell of phosphorus has been expanded to 5 bonds. After accounting for the expanded valence, there are 5 bonds and hence 10 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 40 - 10 = 30 electrons left to draw: Answer: | |

Basic properties

molar mass | 430.49 g/mol phase | solid (at STP) melting point | 100 °C density | 3.61 g/cm^3 solubility in water | decomposes
molar mass | 430.49 g/mol phase | solid (at STP) melting point | 100 °C density | 3.61 g/cm^3 solubility in water | decomposes

Units

Solid properties (at STP)

density | 3.61 g/cm^3
density | 3.61 g/cm^3

Units

Thermodynamic properties

specific heat of formation Δ_fH° | solid | -6.2695 kJ/g molar heat of formation Δ_fH° | solid | -2699 kJ/mol (at STP)
specific heat of formation Δ_fH° | solid | -6.2695 kJ/g molar heat of formation Δ_fH° | solid | -2699 kJ/mol (at STP)

Chemical identifiers

CAS number | 7789-69-7 PubChem CID number | 62678 PubChem SID number | 24853587 SMILES identifier | P(Br)(Br)(Br)(Br)Br InChI identifier | InChI=1/Br5P/c1-6(2, 3, 4)5 MDL number | MFCD00011437
CAS number | 7789-69-7 PubChem CID number | 62678 PubChem SID number | 24853587 SMILES identifier | P(Br)(Br)(Br)(Br)Br InChI identifier | InChI=1/Br5P/c1-6(2, 3, 4)5 MDL number | MFCD00011437