Input interpretation
![corticotropin | molar mass](../image_source/ed2b402acd4379ace930c138ba9f56f5.png)
corticotropin | molar mass
Result
![Find the molar mass, M, for corticotropin: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_207H_308N_56O_58S Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 207 H (hydrogen) | 308 N (nitrogen) | 56 O (oxygen) | 58 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 207 | 12.011 H (hydrogen) | 308 | 1.008 N (nitrogen) | 56 | 14.007 O (oxygen) | 58 | 15.999 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 207 | 12.011 | 207 × 12.011 = 2486.277 H (hydrogen) | 308 | 1.008 | 308 × 1.008 = 310.464 N (nitrogen) | 56 | 14.007 | 56 × 14.007 = 784.392 O (oxygen) | 58 | 15.999 | 58 × 15.999 = 927.942 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 2486.277 g/mol + 310.464 g/mol + 784.392 g/mol + 927.942 g/mol + 32.06 g/mol = 4541.14 g/mol](../image_source/5575a45533b11f824c7cebe7d0263f61.png)
Find the molar mass, M, for corticotropin: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_207H_308N_56O_58S Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 207 H (hydrogen) | 308 N (nitrogen) | 56 O (oxygen) | 58 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 207 | 12.011 H (hydrogen) | 308 | 1.008 N (nitrogen) | 56 | 14.007 O (oxygen) | 58 | 15.999 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 207 | 12.011 | 207 × 12.011 = 2486.277 H (hydrogen) | 308 | 1.008 | 308 × 1.008 = 310.464 N (nitrogen) | 56 | 14.007 | 56 × 14.007 = 784.392 O (oxygen) | 58 | 15.999 | 58 × 15.999 = 927.942 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 2486.277 g/mol + 310.464 g/mol + 784.392 g/mol + 927.942 g/mol + 32.06 g/mol = 4541.14 g/mol
Unit conversion
![4.5411 kg/mol (kilograms per mole)](../image_source/c9b277f16391ed98262765be4fd3bb08.png)
4.5411 kg/mol (kilograms per mole)
Comparisons
![≈ 6.3 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/e5a0d9741c75c65c2b671b35e3eb9ffe.png)
≈ 6.3 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 23 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/012d8d1789bfcb44aa8131793e23a9ea.png)
≈ 23 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 78 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/1cfff32c4aeff664cef01a71b895e218.png)
≈ 78 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7.5×10^-21 grams | 7.5×10^-24 kg (kilograms) | 4541 u (unified atomic mass units) | 4.5 kDa (kilodaltons)](../image_source/83b831cbccf7ffa69e23c389e32d2845.png)
Mass of a molecule m from m = M/N_A: | 7.5×10^-21 grams | 7.5×10^-24 kg (kilograms) | 4541 u (unified atomic mass units) | 4.5 kDa (kilodaltons)
![Relative molecular mass M_r from M_r = M_u/M: | 4541](../image_source/61210d4236bba2f160f70964ffb6bf77.png)
Relative molecular mass M_r from M_r = M_u/M: | 4541