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KOH + CH3CH2COOH = H2O + CH3CH2COOK

Input interpretation

KOH potassium hydroxide + CH_3CH_2COOH propionic acid ⟶ H_2O water + CH3CH2COOK
KOH potassium hydroxide + CH_3CH_2COOH propionic acid ⟶ H_2O water + CH3CH2COOK

Balanced equation

Balance the chemical equation algebraically: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 CH_3CH_2COOH ⟶ c_3 H_2O + c_4 CH3CH2COOK Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O and C: H: | c_1 + 6 c_2 = 2 c_3 + 5 c_4 K: | c_1 = c_4 O: | c_1 + 2 c_2 = c_3 + 2 c_4 C: | 3 c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK
Balance the chemical equation algebraically: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 CH_3CH_2COOH ⟶ c_3 H_2O + c_4 CH3CH2COOK Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O and C: H: | c_1 + 6 c_2 = 2 c_3 + 5 c_4 K: | c_1 = c_4 O: | c_1 + 2 c_2 = c_3 + 2 c_4 C: | 3 c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK

Structures

+ ⟶ + CH3CH2COOK
+ ⟶ + CH3CH2COOK

Names

potassium hydroxide + propionic acid ⟶ water + CH3CH2COOK
potassium hydroxide + propionic acid ⟶ water + CH3CH2COOK

Equilibrium constant

Construct the equilibrium constant, K, expression for: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 1 | -1 CH_3CH_2COOH | 1 | -1 H_2O | 1 | 1 CH3CH2COOK | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 1 | -1 | ([KOH])^(-1) CH_3CH_2COOH | 1 | -1 | ([CH3CH2COOH])^(-1) H_2O | 1 | 1 | [H2O] CH3CH2COOK | 1 | 1 | [CH3CH2COOK] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-1) ([CH3CH2COOH])^(-1) [H2O] [CH3CH2COOK] = ([H2O] [CH3CH2COOK])/([KOH] [CH3CH2COOH])
Construct the equilibrium constant, K, expression for: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 1 | -1 CH_3CH_2COOH | 1 | -1 H_2O | 1 | 1 CH3CH2COOK | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 1 | -1 | ([KOH])^(-1) CH_3CH_2COOH | 1 | -1 | ([CH3CH2COOH])^(-1) H_2O | 1 | 1 | [H2O] CH3CH2COOK | 1 | 1 | [CH3CH2COOK] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-1) ([CH3CH2COOH])^(-1) [H2O] [CH3CH2COOK] = ([H2O] [CH3CH2COOK])/([KOH] [CH3CH2COOH])

Rate of reaction

Construct the rate of reaction expression for: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 1 | -1 CH_3CH_2COOH | 1 | -1 H_2O | 1 | 1 CH3CH2COOK | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 1 | -1 | -(Δ[KOH])/(Δt) CH_3CH_2COOH | 1 | -1 | -(Δ[CH3CH2COOH])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) CH3CH2COOK | 1 | 1 | (Δ[CH3CH2COOK])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[KOH])/(Δt) = -(Δ[CH3CH2COOH])/(Δt) = (Δ[H2O])/(Δt) = (Δ[CH3CH2COOK])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: KOH + CH_3CH_2COOH ⟶ H_2O + CH3CH2COOK Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 1 | -1 CH_3CH_2COOH | 1 | -1 H_2O | 1 | 1 CH3CH2COOK | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 1 | -1 | -(Δ[KOH])/(Δt) CH_3CH_2COOH | 1 | -1 | -(Δ[CH3CH2COOH])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) CH3CH2COOK | 1 | 1 | (Δ[CH3CH2COOK])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[KOH])/(Δt) = -(Δ[CH3CH2COOH])/(Δt) = (Δ[H2O])/(Δt) = (Δ[CH3CH2COOK])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| potassium hydroxide | propionic acid | water | CH3CH2COOK formula | KOH | CH_3CH_2COOH | H_2O | CH3CH2COOK Hill formula | HKO | C_3H_6O_2 | H_2O | C3H5KO2 name | potassium hydroxide | propionic acid | water |
| potassium hydroxide | propionic acid | water | CH3CH2COOK formula | KOH | CH_3CH_2COOH | H_2O | CH3CH2COOK Hill formula | HKO | C_3H_6O_2 | H_2O | C3H5KO2 name | potassium hydroxide | propionic acid | water |

Substance properties

| potassium hydroxide | propionic acid | water | CH3CH2COOK molar mass | 56.105 g/mol | 74.08 g/mol | 18.015 g/mol | 112.17 g/mol phase | solid (at STP) | liquid (at STP) | liquid (at STP) | melting point | 406 °C | -23.5 °C | 0 °C | boiling point | 1327 °C | 141 °C | 99.9839 °C | density | 2.044 g/cm^3 | 0.993 g/cm^3 | 1 g/cm^3 | solubility in water | soluble | miscible | | surface tension | | 0.02721 N/m | 0.0728 N/m | dynamic viscosity | 0.001 Pa s (at 550 °C) | 0.00103 Pa s (at 25 °C) | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |
| potassium hydroxide | propionic acid | water | CH3CH2COOK molar mass | 56.105 g/mol | 74.08 g/mol | 18.015 g/mol | 112.17 g/mol phase | solid (at STP) | liquid (at STP) | liquid (at STP) | melting point | 406 °C | -23.5 °C | 0 °C | boiling point | 1327 °C | 141 °C | 99.9839 °C | density | 2.044 g/cm^3 | 0.993 g/cm^3 | 1 g/cm^3 | solubility in water | soluble | miscible | | surface tension | | 0.02721 N/m | 0.0728 N/m | dynamic viscosity | 0.001 Pa s (at 550 °C) | 0.00103 Pa s (at 25 °C) | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units

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