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molar mass of dioxathion

Input interpretation

dioxathion | molar mass
dioxathion | molar mass

Result

Find the molar mass, M, for dioxathion: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_12H_26O_6P_2S_4 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 12  H (hydrogen) | 26  O (oxygen) | 6  P (phosphorus) | 2  S (sulfur) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 12 | 12.011  H (hydrogen) | 26 | 1.008  O (oxygen) | 6 | 15.999  P (phosphorus) | 2 | 30.973761998  S (sulfur) | 4 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132  H (hydrogen) | 26 | 1.008 | 26 × 1.008 = 26.208  O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994  P (phosphorus) | 2 | 30.973761998 | 2 × 30.973761998 = 61.947523996  S (sulfur) | 4 | 32.06 | 4 × 32.06 = 128.24  M = 144.132 g/mol + 26.208 g/mol + 95.994 g/mol + 61.947523996 g/mol + 128.24 g/mol = 456.52 g/mol
Find the molar mass, M, for dioxathion: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_12H_26O_6P_2S_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 12 H (hydrogen) | 26 O (oxygen) | 6 P (phosphorus) | 2 S (sulfur) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 12 | 12.011 H (hydrogen) | 26 | 1.008 O (oxygen) | 6 | 15.999 P (phosphorus) | 2 | 30.973761998 S (sulfur) | 4 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 H (hydrogen) | 26 | 1.008 | 26 × 1.008 = 26.208 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 P (phosphorus) | 2 | 30.973761998 | 2 × 30.973761998 = 61.947523996 S (sulfur) | 4 | 32.06 | 4 × 32.06 = 128.24 M = 144.132 g/mol + 26.208 g/mol + 95.994 g/mol + 61.947523996 g/mol + 128.24 g/mol = 456.52 g/mol

Unit conversion

0.4565 kg/mol (kilograms per mole)
0.4565 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.4 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.4 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 7.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 7.8 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 7.6×10^-22 grams  | 7.6×10^-25 kg (kilograms)  | 457 u (unified atomic mass units)  | 457 Da (daltons)
Mass of a molecule m from m = M/N_A: | 7.6×10^-22 grams | 7.6×10^-25 kg (kilograms) | 457 u (unified atomic mass units) | 457 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 457
Relative molecular mass M_r from M_r = M_u/M: | 457