HNO3 + NiS = H2O + H2SO4 + NO + Ni(NO3)2

Input interpretation

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nitric acid + nickel(II) sulfide ⟶ water + sulfuric acid + nitric oxide + nickel(II) nitrate

Balanced equation

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$Balance the chemical equation algebraically: + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Ni and S: H: | c_1 = 2 c_3 + 2 c_4 N: | c_1 = c_5 + 2 c_6 O: | 3 c_1 = c_3 + 4 c_4 + c_5 + 6 c_6 Ni: | c_2 = c_6 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 14/3 c_2 = 1 c_3 = 4/3 c_4 = 1 c_5 = 8/3 c_6 = 1 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 14 c_2 = 3 c_3 = 4 c_4 = 3 c_5 = 8 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 14 + 3 ⟶ 4 + 3 + 8 + 3$

Balance the chemical equation algebraically: + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Ni and S: H: | c_1 = 2 c_3 + 2 c_4 N: | c_1 = c_5 + 2 c_6 O: | 3 c_1 = c_3 + 4 c_4 + c_5 + 6 c_6 Ni: | c_2 = c_6 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 14/3 c_2 = 1 c_3 = 4/3 c_4 = 1 c_5 = 8/3 c_6 = 1 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 14 c_2 = 3 c_3 = 4 c_4 = 3 c_5 = 8 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 14 + 3 ⟶ 4 + 3 + 8 + 3