Input interpretation
tritriacontanol
Chemical names and formulas
formula | C_33H_68O_1 Hill formula | C_33H_68O name | tritriacontanol IUPAC name | 1-tritriacontanol alternate names | 1-tritriacontanol | n-tritriacontanol mass fractions | C (carbon) 82.4% | H (hydrogen) 14.3% | O (oxygen) 3.33%
Lewis structure
Draw the Lewis structure of tritriacontanol. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms: 33 n_C, val + 68 n_H, val + n_O, val = 206 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): 33 n_C, full + 68 n_H, full + n_O, full = 408 Subtracting these two numbers shows that 408 - 206 = 202 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 101 bonds and hence 202 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 206 - 202 = 4 electrons left to draw: Answer: | |
Basic properties
molar mass | 480.9 g/mol
Units
Chemical identifiers
PubChem CID number | 156150 SMILES identifier | CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCO InChI identifier | InChI=1S/C33H68O/c1-2-3-4-5-6-7-8-9-10-11-12-13-14-15-16-17-18-19-20-21-22-23-24-25-26-27-28-29-30-31-32-33-34/h34H, 2-33H2, 1H3