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H2O + I2 + AgNO3 = HNO3 + AgI + AgIO3

Input interpretation

H_2O water + I_2 iodine + AgNO_3 silver nitrate ⟶ HNO_3 nitric acid + AgI silver(I) iodide + AgIO_3 silver iodate
H_2O water + I_2 iodine + AgNO_3 silver nitrate ⟶ HNO_3 nitric acid + AgI silver(I) iodide + AgIO_3 silver iodate

Balanced equation

Balance the chemical equation algebraically: H_2O + I_2 + AgNO_3 ⟶ HNO_3 + AgI + AgIO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 I_2 + c_3 AgNO_3 ⟶ c_4 HNO_3 + c_5 AgI + c_6 AgIO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, I, Ag and N: H: | 2 c_1 = c_4 O: | c_1 + 3 c_3 = 3 c_4 + 3 c_6 I: | 2 c_2 = c_5 + c_6 Ag: | c_3 = c_5 + c_6 N: | c_3 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 3 c_3 = 6 c_4 = 6 c_5 = 5 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 3 H_2O + 3 I_2 + 6 AgNO_3 ⟶ 6 HNO_3 + 5 AgI + AgIO_3
Balance the chemical equation algebraically: H_2O + I_2 + AgNO_3 ⟶ HNO_3 + AgI + AgIO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 I_2 + c_3 AgNO_3 ⟶ c_4 HNO_3 + c_5 AgI + c_6 AgIO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, I, Ag and N: H: | 2 c_1 = c_4 O: | c_1 + 3 c_3 = 3 c_4 + 3 c_6 I: | 2 c_2 = c_5 + c_6 Ag: | c_3 = c_5 + c_6 N: | c_3 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 3 c_3 = 6 c_4 = 6 c_5 = 5 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 H_2O + 3 I_2 + 6 AgNO_3 ⟶ 6 HNO_3 + 5 AgI + AgIO_3

Structures

 + + ⟶ + +
+ + ⟶ + +

Names

water + iodine + silver nitrate ⟶ nitric acid + silver(I) iodide + silver iodate
water + iodine + silver nitrate ⟶ nitric acid + silver(I) iodide + silver iodate

Reaction thermodynamics

Gibbs free energy

 | water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate molecular free energy | -237.1 kJ/mol | 0 kJ/mol | -33.4 kJ/mol | -80.7 kJ/mol | -66.2 kJ/mol | -93.7 kJ/mol total free energy | -711.3 kJ/mol | 0 kJ/mol | -200.4 kJ/mol | -484.2 kJ/mol | -331 kJ/mol | -93.7 kJ/mol  | G_initial = -911.7 kJ/mol | | | G_final = -908.9 kJ/mol | |  ΔG_rxn^0 | -908.9 kJ/mol - -911.7 kJ/mol = 2.8 kJ/mol (endergonic) | | | | |
| water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate molecular free energy | -237.1 kJ/mol | 0 kJ/mol | -33.4 kJ/mol | -80.7 kJ/mol | -66.2 kJ/mol | -93.7 kJ/mol total free energy | -711.3 kJ/mol | 0 kJ/mol | -200.4 kJ/mol | -484.2 kJ/mol | -331 kJ/mol | -93.7 kJ/mol | G_initial = -911.7 kJ/mol | | | G_final = -908.9 kJ/mol | | ΔG_rxn^0 | -908.9 kJ/mol - -911.7 kJ/mol = 2.8 kJ/mol (endergonic) | | | | |

Entropy

 | water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate molecular entropy | 69.91 J/(mol K) | 116.1 J/(mol K) | 140.9 J/(mol K) | 156 J/(mol K) | 115.5 J/(mol K) | 149.4 J/(mol K) total entropy | 209.7 J/(mol K) | 348.4 J/(mol K) | 845.4 J/(mol K) | 936 J/(mol K) | 577.5 J/(mol K) | 149.4 J/(mol K)  | S_initial = 1404 J/(mol K) | | | S_final = 1663 J/(mol K) | |  ΔS_rxn^0 | 1663 J/(mol K) - 1404 J/(mol K) = 259.4 J/(mol K) (endoentropic) | | | | |
| water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate molecular entropy | 69.91 J/(mol K) | 116.1 J/(mol K) | 140.9 J/(mol K) | 156 J/(mol K) | 115.5 J/(mol K) | 149.4 J/(mol K) total entropy | 209.7 J/(mol K) | 348.4 J/(mol K) | 845.4 J/(mol K) | 936 J/(mol K) | 577.5 J/(mol K) | 149.4 J/(mol K) | S_initial = 1404 J/(mol K) | | | S_final = 1663 J/(mol K) | | ΔS_rxn^0 | 1663 J/(mol K) - 1404 J/(mol K) = 259.4 J/(mol K) (endoentropic) | | | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2O + I_2 + AgNO_3 ⟶ HNO_3 + AgI + AgIO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 H_2O + 3 I_2 + 6 AgNO_3 ⟶ 6 HNO_3 + 5 AgI + AgIO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 3 | -3 I_2 | 3 | -3 AgNO_3 | 6 | -6 HNO_3 | 6 | 6 AgI | 5 | 5 AgIO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 3 | -3 | ([H2O])^(-3) I_2 | 3 | -3 | ([I2])^(-3) AgNO_3 | 6 | -6 | ([AgNO3])^(-6) HNO_3 | 6 | 6 | ([HNO3])^6 AgI | 5 | 5 | ([AgI])^5 AgIO_3 | 1 | 1 | [AgIO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([H2O])^(-3) ([I2])^(-3) ([AgNO3])^(-6) ([HNO3])^6 ([AgI])^5 [AgIO3] = (([HNO3])^6 ([AgI])^5 [AgIO3])/(([H2O])^3 ([I2])^3 ([AgNO3])^6)
Construct the equilibrium constant, K, expression for: H_2O + I_2 + AgNO_3 ⟶ HNO_3 + AgI + AgIO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 H_2O + 3 I_2 + 6 AgNO_3 ⟶ 6 HNO_3 + 5 AgI + AgIO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 3 | -3 I_2 | 3 | -3 AgNO_3 | 6 | -6 HNO_3 | 6 | 6 AgI | 5 | 5 AgIO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 3 | -3 | ([H2O])^(-3) I_2 | 3 | -3 | ([I2])^(-3) AgNO_3 | 6 | -6 | ([AgNO3])^(-6) HNO_3 | 6 | 6 | ([HNO3])^6 AgI | 5 | 5 | ([AgI])^5 AgIO_3 | 1 | 1 | [AgIO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-3) ([I2])^(-3) ([AgNO3])^(-6) ([HNO3])^6 ([AgI])^5 [AgIO3] = (([HNO3])^6 ([AgI])^5 [AgIO3])/(([H2O])^3 ([I2])^3 ([AgNO3])^6)

Rate of reaction

Construct the rate of reaction expression for: H_2O + I_2 + AgNO_3 ⟶ HNO_3 + AgI + AgIO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 H_2O + 3 I_2 + 6 AgNO_3 ⟶ 6 HNO_3 + 5 AgI + AgIO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 3 | -3 I_2 | 3 | -3 AgNO_3 | 6 | -6 HNO_3 | 6 | 6 AgI | 5 | 5 AgIO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 3 | -3 | -1/3 (Δ[H2O])/(Δt) I_2 | 3 | -3 | -1/3 (Δ[I2])/(Δt) AgNO_3 | 6 | -6 | -1/6 (Δ[AgNO3])/(Δt) HNO_3 | 6 | 6 | 1/6 (Δ[HNO3])/(Δt) AgI | 5 | 5 | 1/5 (Δ[AgI])/(Δt) AgIO_3 | 1 | 1 | (Δ[AgIO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/3 (Δ[H2O])/(Δt) = -1/3 (Δ[I2])/(Δt) = -1/6 (Δ[AgNO3])/(Δt) = 1/6 (Δ[HNO3])/(Δt) = 1/5 (Δ[AgI])/(Δt) = (Δ[AgIO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2O + I_2 + AgNO_3 ⟶ HNO_3 + AgI + AgIO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 H_2O + 3 I_2 + 6 AgNO_3 ⟶ 6 HNO_3 + 5 AgI + AgIO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 3 | -3 I_2 | 3 | -3 AgNO_3 | 6 | -6 HNO_3 | 6 | 6 AgI | 5 | 5 AgIO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 3 | -3 | -1/3 (Δ[H2O])/(Δt) I_2 | 3 | -3 | -1/3 (Δ[I2])/(Δt) AgNO_3 | 6 | -6 | -1/6 (Δ[AgNO3])/(Δt) HNO_3 | 6 | 6 | 1/6 (Δ[HNO3])/(Δt) AgI | 5 | 5 | 1/5 (Δ[AgI])/(Δt) AgIO_3 | 1 | 1 | (Δ[AgIO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[H2O])/(Δt) = -1/3 (Δ[I2])/(Δt) = -1/6 (Δ[AgNO3])/(Δt) = 1/6 (Δ[HNO3])/(Δt) = 1/5 (Δ[AgI])/(Δt) = (Δ[AgIO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate formula | H_2O | I_2 | AgNO_3 | HNO_3 | AgI | AgIO_3 name | water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate IUPAC name | water | molecular iodine | silver nitrate | nitric acid | silver iodide | silver iodate
| water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate formula | H_2O | I_2 | AgNO_3 | HNO_3 | AgI | AgIO_3 name | water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate IUPAC name | water | molecular iodine | silver nitrate | nitric acid | silver iodide | silver iodate

Substance properties

 | water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate molar mass | 18.015 g/mol | 253.80894 g/mol | 169.87 g/mol | 63.012 g/mol | 234.7727 g/mol | 282.77 g/mol phase | liquid (at STP) | solid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) | solid (at STP) melting point | 0 °C | 113 °C | 212 °C | -41.6 °C | 557 °C | 200 °C boiling point | 99.9839 °C | 184 °C | | 83 °C | 1506 °C | 1150 °C density | 1 g/cm^3 | 4.94 g/cm^3 | | 1.5129 g/cm^3 | 5.68 g/cm^3 | 5.525 g/cm^3 solubility in water | | | soluble | miscible | slightly soluble |  surface tension | 0.0728 N/m | | | | |  dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | 0.00227 Pa s (at 116 °C) | | 7.6×10^-4 Pa s (at 25 °C) | |  odor | odorless | | odorless | | |
| water | iodine | silver nitrate | nitric acid | silver(I) iodide | silver iodate molar mass | 18.015 g/mol | 253.80894 g/mol | 169.87 g/mol | 63.012 g/mol | 234.7727 g/mol | 282.77 g/mol phase | liquid (at STP) | solid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) | solid (at STP) melting point | 0 °C | 113 °C | 212 °C | -41.6 °C | 557 °C | 200 °C boiling point | 99.9839 °C | 184 °C | | 83 °C | 1506 °C | 1150 °C density | 1 g/cm^3 | 4.94 g/cm^3 | | 1.5129 g/cm^3 | 5.68 g/cm^3 | 5.525 g/cm^3 solubility in water | | | soluble | miscible | slightly soluble | surface tension | 0.0728 N/m | | | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | 0.00227 Pa s (at 116 °C) | | 7.6×10^-4 Pa s (at 25 °C) | | odor | odorless | | odorless | | |

Units