MnO2KClOK2CO3 = K2MnO4KClCO2

MnO2KClOK2CO3 ⟶ K2MnO4KClCO2

Balance the chemical equation algebraically: MnO2KClOK2CO3 ⟶ K2MnO4KClCO2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 MnO2KClOK2CO3 ⟶ c_2 K2MnO4KClCO2 Set the number of atoms in the reactants equal to the number of atoms in the products for Mn, O, K, Cl and C: Mn: | c_1 = c_2 O: | 6 c_1 = 6 c_2 K: | 3 c_1 = 3 c_2 Cl: | c_1 = c_2 C: | c_1 = c_2 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | MnO2KClOK2CO3 ⟶ K2MnO4KClCO2

MnO2KClOK2CO3 ⟶ K2MnO4KClCO2

MnO2KClOK2CO3 ⟶ K2MnO4KClCO2

Construct the equilibrium constant, K, expression for: MnO2KClOK2CO3 ⟶ K2MnO4KClCO2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: MnO2KClOK2CO3 ⟶ K2MnO4KClCO2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i MnO2KClOK2CO3 | 1 | -1 K2MnO4KClCO2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression MnO2KClOK2CO3 | 1 | -1 | ([MnO2KClOK2CO3])^(-1) K2MnO4KClCO2 | 1 | 1 | [K2MnO4KClCO2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([MnO2KClOK2CO3])^(-1) [K2MnO4KClCO2] = ([K2MnO4KClCO2])/([MnO2KClOK2CO3])

Construct the rate of reaction expression for: MnO2KClOK2CO3 ⟶ K2MnO4KClCO2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: MnO2KClOK2CO3 ⟶ K2MnO4KClCO2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i MnO2KClOK2CO3 | 1 | -1 K2MnO4KClCO2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term MnO2KClOK2CO3 | 1 | -1 | -(Δ[MnO2KClOK2CO3])/(Δt) K2MnO4KClCO2 | 1 | 1 | (Δ[K2MnO4KClCO2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[MnO2KClOK2CO3])/(Δt) = (Δ[K2MnO4KClCO2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| MnO2KClOK2CO3 | K2MnO4KClCO2 formula | MnO2KClOK2CO3 | K2MnO4KClCO2 Hill formula | CClK3MnO6 | CClK3MnO6

| MnO2KClOK2CO3 | K2MnO4KClCO2 molar mass | 315.69 g/mol | 315.69 g/mol