Input interpretation
![phosphorus pentoxide](../image_source/ca724cc779db1e664c43e69d7baf4340.png)
phosphorus pentoxide
Chemical names and formulas
![formula | P_4O_10 Hill formula | O_10P_4 name | phosphorus pentoxide alternate names | phosphoric anhydride | phosphorus(V) oxide mass fractions | O (oxygen) 56.4% | P (phosphorus) 43.6%](../image_source/ca8e0d1748504ae20f827c6a1dafacce.png)
formula | P_4O_10 Hill formula | O_10P_4 name | phosphorus pentoxide alternate names | phosphoric anhydride | phosphorus(V) oxide mass fractions | O (oxygen) 56.4% | P (phosphorus) 43.6%
Lewis structure
![Draw the Lewis structure of phosphorus pentoxide. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds: Count the total valence electrons of the oxygen (n_O, val = 6) and phosphorus (n_P, val = 5) atoms: 10 n_O, val + 4 n_P, val = 80 Calculate the number of electrons needed to completely fill the valence shells for oxygen (n_O, full = 8) and phosphorus (n_P, full = 8): 10 n_O, full + 4 n_P, full = 112 Subtracting these two numbers shows that 112 - 80 = 32 bonding electrons are needed. Each bond has two electrons, so we expect that the above diagram has all the necessary bonds. However, to minimize formal charge oxygen wants 2 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom: In order to minimize their formal charge, atoms with large electronegativities can force atoms with smaller electronegativities on period 3 or higher to expand their valence shells. The electronegativities of the atoms are 2.19 (phosphorus) and 3.44 (oxygen). Because the electronegativity of phosphorus is smaller than the electronegativity of oxygen, expand the valence shell of phosphorus to 5 bonds in 4 places. Therefore we add a total of 4 bonds to the diagram: Answer: | |](../image_source/f2269dfaefeca752de29c72ebc553754.png)
Draw the Lewis structure of phosphorus pentoxide. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds: Count the total valence electrons of the oxygen (n_O, val = 6) and phosphorus (n_P, val = 5) atoms: 10 n_O, val + 4 n_P, val = 80 Calculate the number of electrons needed to completely fill the valence shells for oxygen (n_O, full = 8) and phosphorus (n_P, full = 8): 10 n_O, full + 4 n_P, full = 112 Subtracting these two numbers shows that 112 - 80 = 32 bonding electrons are needed. Each bond has two electrons, so we expect that the above diagram has all the necessary bonds. However, to minimize formal charge oxygen wants 2 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom: In order to minimize their formal charge, atoms with large electronegativities can force atoms with smaller electronegativities on period 3 or higher to expand their valence shells. The electronegativities of the atoms are 2.19 (phosphorus) and 3.44 (oxygen). Because the electronegativity of phosphorus is smaller than the electronegativity of oxygen, expand the valence shell of phosphorus to 5 bonds in 4 places. Therefore we add a total of 4 bonds to the diagram: Answer: | |
3D structure
![3D structure](../image_source/15649fa7e5708beca9dfa02bf0698665.png)
3D structure
Basic properties
![molar mass | 283.89 g/mol phase | solid (at STP) melting point | 340 °C density | 2.3 g/cm^3](../image_source/06b4372dec7399ff7ccb70872c1dd8db.png)
molar mass | 283.89 g/mol phase | solid (at STP) melting point | 340 °C density | 2.3 g/cm^3
Units
Solid properties (at STP)
![density | 2.3 g/cm^3 vapor pressure | 0.9998 mmHg](../image_source/92242b0da920a5f5cbc048959fd5cb44.png)
density | 2.3 g/cm^3 vapor pressure | 0.9998 mmHg
Units
Thermodynamic properties
![specific free energy of formation Δ_fG° | solid | -9.504 kJ/g molar free energy of formation Δ_fG° | solid | -2698 kJ/mol specific heat of formation Δ_fH° | solid | -10.51 kJ/g molar heat of formation Δ_fH° | solid | -2984 kJ/mol specific entropy S° | solid | 0.8067 J/(g K) molar entropy S° | solid | 229 J/(mol K) molar heat of vaporization | 94.9 kJ/mol | specific heat of vaporization | 0.3343 kJ/g | molar heat of fusion | 27.2 kJ/mol | specific heat of fusion | 0.0958 kJ/g | (at STP)](../image_source/9a9b89b052178f61af956cd7a4ff42a7.png)
specific free energy of formation Δ_fG° | solid | -9.504 kJ/g molar free energy of formation Δ_fG° | solid | -2698 kJ/mol specific heat of formation Δ_fH° | solid | -10.51 kJ/g molar heat of formation Δ_fH° | solid | -2984 kJ/mol specific entropy S° | solid | 0.8067 J/(g K) molar entropy S° | solid | 229 J/(mol K) molar heat of vaporization | 94.9 kJ/mol | specific heat of vaporization | 0.3343 kJ/g | molar heat of fusion | 27.2 kJ/mol | specific heat of fusion | 0.0958 kJ/g | (at STP)
Chemical identifiers
![CAS number | 1314-56-3 PubChem CID number | 14812 SMILES identifier | O=P12OP3(=O)OP(=O)(O1)OP(=O)(O2)O3 InChI identifier | InChI=1/O10P4/c1-11-5-12(2)8-13(3, 6-11)10-14(4, 7-11)9-12 RTECS number | TH3945000 MDL number | MFCD00011440](../image_source/4083c54874b21c71b5e069392fa2aea2.png)
CAS number | 1314-56-3 PubChem CID number | 14812 SMILES identifier | O=P12OP3(=O)OP(=O)(O1)OP(=O)(O2)O3 InChI identifier | InChI=1/O10P4/c1-11-5-12(2)8-13(3, 6-11)10-14(4, 7-11)9-12 RTECS number | TH3945000 MDL number | MFCD00011440