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molar mass of 1,1,1,3,3-pentafluoropropane

Input interpretation

1, 1, 1, 3, 3-pentafluoropropane | molar mass
1, 1, 1, 3, 3-pentafluoropropane | molar mass

Result

Find the molar mass, M, for 1, 1, 1, 3, 3-pentafluoropropane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_3H_3F_5 Use the chemical formula, C_3H_3F_5, to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 3  F (fluorine) | 5  H (hydrogen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 3 | 12.011  F (fluorine) | 5 | 18.998403163  H (hydrogen) | 3 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033  F (fluorine) | 5 | 18.998403163 | 5 × 18.998403163 = 94.992015815  H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024  M = 36.033 g/mol + 94.992015815 g/mol + 3.024 g/mol = 134.049 g/mol
Find the molar mass, M, for 1, 1, 1, 3, 3-pentafluoropropane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_3H_3F_5 Use the chemical formula, C_3H_3F_5, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 3 F (fluorine) | 5 H (hydrogen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 3 | 12.011 F (fluorine) | 5 | 18.998403163 H (hydrogen) | 3 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033 F (fluorine) | 5 | 18.998403163 | 5 × 18.998403163 = 94.992015815 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 M = 36.033 g/mol + 94.992015815 g/mol + 3.024 g/mol = 134.049 g/mol

Unit conversion

0.13405 kg/mol (kilograms per mole)
0.13405 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.69 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.69 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 2.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 2.3 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 2.2×10^-22 grams  | 2.2×10^-25 kg (kilograms)  | 134 u (unified atomic mass units)  | 134 Da (daltons)
Mass of a molecule m from m = M/N_A: | 2.2×10^-22 grams | 2.2×10^-25 kg (kilograms) | 134 u (unified atomic mass units) | 134 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 134
Relative molecular mass M_r from M_r = M_u/M: | 134