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mass fractions of 3,4-dimethylphenylzinc iodide

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3, 4-dimethylphenylzinc iodide | elemental composition
3, 4-dimethylphenylzinc iodide | elemental composition

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Find the elemental composition for 3, 4-dimethylphenylzinc iodide in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: (CH_3)_2C_6H_3ZnI Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule:  | number of atoms  C (carbon) | 8  H (hydrogen) | 9  I (iodine) | 1  Zn (zinc) | 1  N_atoms = 8 + 9 + 1 + 1 = 19 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work:  | number of atoms | atom fraction  C (carbon) | 8 | 8/19  H (hydrogen) | 9 | 9/19  I (iodine) | 1 | 1/19  Zn (zinc) | 1 | 1/19 Check: 8/19 + 9/19 + 1/19 + 1/19 = 1 Compute atom percents using the atom fractions:  | number of atoms | atom percent  C (carbon) | 8 | 8/19 × 100% = 42.1%  H (hydrogen) | 9 | 9/19 × 100% = 47.4%  I (iodine) | 1 | 1/19 × 100% = 5.26%  Zn (zinc) | 1 | 1/19 × 100% = 5.26% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table:  | number of atoms | atom percent | atomic mass/u  C (carbon) | 8 | 42.1% | 12.011  H (hydrogen) | 9 | 47.4% | 1.008  I (iodine) | 1 | 5.26% | 126.90447  Zn (zinc) | 1 | 5.26% | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m:  | number of atoms | atom percent | atomic mass/u | mass/u  C (carbon) | 8 | 42.1% | 12.011 | 8 × 12.011 = 96.088  H (hydrogen) | 9 | 47.4% | 1.008 | 9 × 1.008 = 9.072  I (iodine) | 1 | 5.26% | 126.90447 | 1 × 126.90447 = 126.90447  Zn (zinc) | 1 | 5.26% | 65.38 | 1 × 65.38 = 65.38  m = 96.088 u + 9.072 u + 126.90447 u + 65.38 u = 297.44447 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work:  | number of atoms | atom percent | mass fraction  C (carbon) | 8 | 42.1% | 96.088/297.44447  H (hydrogen) | 9 | 47.4% | 9.072/297.44447  I (iodine) | 1 | 5.26% | 126.90447/297.44447  Zn (zinc) | 1 | 5.26% | 65.38/297.44447 Check: 96.088/297.44447 + 9.072/297.44447 + 126.90447/297.44447 + 65.38/297.44447 = 1 Compute mass percents using the mass fractions: Answer: |   | | number of atoms | atom percent | mass percent  C (carbon) | 8 | 42.1% | 96.088/297.44447 × 100% = 32.30%  H (hydrogen) | 9 | 47.4% | 9.072/297.44447 × 100% = 3.050%  I (iodine) | 1 | 5.26% | 126.90447/297.44447 × 100% = 42.66%  Zn (zinc) | 1 | 5.26% | 65.38/297.44447 × 100% = 21.98%
Find the elemental composition for 3, 4-dimethylphenylzinc iodide in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: (CH_3)_2C_6H_3ZnI Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms C (carbon) | 8 H (hydrogen) | 9 I (iodine) | 1 Zn (zinc) | 1 N_atoms = 8 + 9 + 1 + 1 = 19 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction C (carbon) | 8 | 8/19 H (hydrogen) | 9 | 9/19 I (iodine) | 1 | 1/19 Zn (zinc) | 1 | 1/19 Check: 8/19 + 9/19 + 1/19 + 1/19 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent C (carbon) | 8 | 8/19 × 100% = 42.1% H (hydrogen) | 9 | 9/19 × 100% = 47.4% I (iodine) | 1 | 1/19 × 100% = 5.26% Zn (zinc) | 1 | 1/19 × 100% = 5.26% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u C (carbon) | 8 | 42.1% | 12.011 H (hydrogen) | 9 | 47.4% | 1.008 I (iodine) | 1 | 5.26% | 126.90447 Zn (zinc) | 1 | 5.26% | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u C (carbon) | 8 | 42.1% | 12.011 | 8 × 12.011 = 96.088 H (hydrogen) | 9 | 47.4% | 1.008 | 9 × 1.008 = 9.072 I (iodine) | 1 | 5.26% | 126.90447 | 1 × 126.90447 = 126.90447 Zn (zinc) | 1 | 5.26% | 65.38 | 1 × 65.38 = 65.38 m = 96.088 u + 9.072 u + 126.90447 u + 65.38 u = 297.44447 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction C (carbon) | 8 | 42.1% | 96.088/297.44447 H (hydrogen) | 9 | 47.4% | 9.072/297.44447 I (iodine) | 1 | 5.26% | 126.90447/297.44447 Zn (zinc) | 1 | 5.26% | 65.38/297.44447 Check: 96.088/297.44447 + 9.072/297.44447 + 126.90447/297.44447 + 65.38/297.44447 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent C (carbon) | 8 | 42.1% | 96.088/297.44447 × 100% = 32.30% H (hydrogen) | 9 | 47.4% | 9.072/297.44447 × 100% = 3.050% I (iodine) | 1 | 5.26% | 126.90447/297.44447 × 100% = 42.66% Zn (zinc) | 1 | 5.26% | 65.38/297.44447 × 100% = 21.98%

Mass fraction pie chart

Mass fraction pie chart
Mass fraction pie chart