Input interpretation
lutetium(III) trifluoromethanesulfonate | molecular mass
Result
Find the molecular mass, m, for lutetium(III) trifluoromethanesulfonate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Lu(CF_3SO_3)_3 Use the chemical formula, Lu(CF_3SO_3)_3, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 3 F (fluorine) | 9 Lu (lutetium) | 1 O (oxygen) | 9 S (sulfur) | 3 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 3 | 12.011 F (fluorine) | 9 | 18.998403163 Lu (lutetium) | 1 | 174.9668 O (oxygen) | 9 | 15.999 S (sulfur) | 3 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033 F (fluorine) | 9 | 18.998403163 | 9 × 18.998403163 = 170.985628467 Lu (lutetium) | 1 | 174.9668 | 1 × 174.9668 = 174.9668 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 S (sulfur) | 3 | 32.06 | 3 × 32.06 = 96.18 m = 36.033 u + 170.985628467 u + 174.9668 u + 143.991 u + 96.18 u = 622.16 u
Unit conversions
622.2 Da (daltons)
0.6222 kDa (kilodaltons)
1.0331×10^-21 grams
1.0331×10^-24 kg (kilograms)
622.2 chemical atomic mass units (unit officially deprecated)
622.4 physical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
≈ 0.86 × molecular mass of fullerene ( ≈ 721 u )
≈ 3.2 × molecular mass of caffeine ( ≈ 194 u )
≈ 11 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 622
Molar mass M from M = m_aN_A: | 622 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 622
Molar mass M from M = m_mN_A: | 622 g/mol (grams per mole)