S + Ba = BaS

S mixed sulfur + Ba barium ⟶ BaS barium sulfide

Balance the chemical equation algebraically: S + Ba ⟶ BaS Add stoichiometric coefficients, c_i, to the reactants and products: c_1 S + c_2 Ba ⟶ c_3 BaS Set the number of atoms in the reactants equal to the number of atoms in the products for S and Ba: S: | c_1 = c_3 Ba: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | S + Ba ⟶ BaS

+ ⟶

mixed sulfur + barium ⟶ barium sulfide

Construct the equilibrium constant, K, expression for: S + Ba ⟶ BaS Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: S + Ba ⟶ BaS Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i S | 1 | -1 Ba | 1 | -1 BaS | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression S | 1 | -1 | ([S])^(-1) Ba | 1 | -1 | ([Ba])^(-1) BaS | 1 | 1 | [BaS] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([S])^(-1) ([Ba])^(-1) [BaS] = ([BaS])/([S] [Ba])

Construct the rate of reaction expression for: S + Ba ⟶ BaS Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: S + Ba ⟶ BaS Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i S | 1 | -1 Ba | 1 | -1 BaS | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term S | 1 | -1 | -(Δ[S])/(Δt) Ba | 1 | -1 | -(Δ[Ba])/(Δt) BaS | 1 | 1 | (Δ[BaS])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[S])/(Δt) = -(Δ[Ba])/(Δt) = (Δ[BaS])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| mixed sulfur | barium | barium sulfide formula | S | Ba | BaS name | mixed sulfur | barium | barium sulfide IUPAC name | sulfur | barium | thioxobarium

| mixed sulfur | barium | barium sulfide molar mass | 32.06 g/mol | 137.327 g/mol | 169.39 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) melting point | 112.8 °C | 725 °C | 1999.85 °C boiling point | 444.7 °C | 1640 °C | density | 2.07 g/cm^3 | 3.6 g/cm^3 | 4.25 g/cm^3 solubility in water | | insoluble | surface tension | | 0.224 N/m |