Input interpretation
hydrogen chloride + potassium iodide + disodium hydrogen arsenate ⟶ water + iodine + sodium chloride + potassium chloride + arsenious acid
Balanced equation
Balance the chemical equation algebraically: + + ⟶ + + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 + c_8 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, I, K, As, Na and O: Cl: | c_1 = c_6 + c_7 H: | c_1 + c_3 = 2 c_4 + 3 c_8 I: | c_2 = 2 c_5 K: | c_2 = c_7 As: | c_3 = c_8 Na: | 2 c_3 = c_6 O: | 4 c_3 = c_4 + 3 c_8 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 2 c_3 = 1 c_4 = 1 c_5 = 1 c_6 = 2 c_7 = 2 c_8 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + 2 + ⟶ + + 2 + 2 +
Structures
+ + ⟶ + + + +
Names
hydrogen chloride + potassium iodide + disodium hydrogen arsenate ⟶ water + iodine + sodium chloride + potassium chloride + arsenious acid
Chemical names and formulas
| hydrogen chloride | potassium iodide | disodium hydrogen arsenate | water | iodine | sodium chloride | potassium chloride | arsenious acid Hill formula | ClH | IK | AsHNa_2O_4 | H_2O | I_2 | ClNa | ClK | AsH_3O_3 name | hydrogen chloride | potassium iodide | disodium hydrogen arsenate | water | iodine | sodium chloride | potassium chloride | arsenious acid IUPAC name | hydrogen chloride | potassium iodide | disodium dioxidoarsinic acid | water | molecular iodine | sodium chloride | potassium chloride | arsorous acid