Input interpretation
![phosphorus(III) iodide](../image_source/64a7fe4d0c6078a2278ae4110ddb71d2.png)
phosphorus(III) iodide
Chemical names and formulas
![formula | PI_3 Hill formula | I_3P name | phosphorus(III) iodide IUPAC name | triiodophosphane alternate names | phosphorous triiodide | phosphorous-triiodide- | phosphorus triiodide | triiodophosphane mass fractions | I (iodine) 92.5% | P (phosphorus) 7.52%](../image_source/405de002d7e0d9fbb14071b565848b34.png)
formula | PI_3 Hill formula | I_3P name | phosphorus(III) iodide IUPAC name | triiodophosphane alternate names | phosphorous triiodide | phosphorous-triiodide- | phosphorus triiodide | triiodophosphane mass fractions | I (iodine) 92.5% | P (phosphorus) 7.52%
Lewis structure
![Draw the Lewis structure of phosphorus(III) iodide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the iodine (n_I, val = 7) and phosphorus (n_P, val = 5) atoms: 3 n_I, val + n_P, val = 26 Calculate the number of electrons needed to completely fill the valence shells for iodine (n_I, full = 8) and phosphorus (n_P, full = 8): 3 n_I, full + n_P, full = 32 Subtracting these two numbers shows that 32 - 26 = 6 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 3 bonds and hence 6 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 26 - 6 = 20 electrons left to draw: Answer: | |](../image_source/25306f9f027b9d96ecb8c7bdc3ade1c8.png)
Draw the Lewis structure of phosphorus(III) iodide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the iodine (n_I, val = 7) and phosphorus (n_P, val = 5) atoms: 3 n_I, val + n_P, val = 26 Calculate the number of electrons needed to completely fill the valence shells for iodine (n_I, full = 8) and phosphorus (n_P, full = 8): 3 n_I, full + n_P, full = 32 Subtracting these two numbers shows that 32 - 26 = 6 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 3 bonds and hence 6 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 26 - 6 = 20 electrons left to draw: Answer: | |
3D structure
![3D structure](../image_source/b39bfb0a05f816d71208cea3bb9f199f.png)
3D structure
Basic properties
![molar mass | 411.68717 g/mol phase | solid (at STP) melting point | 61 °C boiling point | 200 °C density | 4.18 g/cm^3](../image_source/bf4d0830bb51da5503161c0cdefc3cf7.png)
molar mass | 411.68717 g/mol phase | solid (at STP) melting point | 61 °C boiling point | 200 °C density | 4.18 g/cm^3
Units
Solid properties (at STP)
![density | 4.18 g/cm^3](../image_source/9c516eab01f7b4f80c8243280b52a2b0.png)
density | 4.18 g/cm^3
Units
Thermodynamic properties
![specific heat capacity c_p | gas | 0.1904 J/(g K) molar heat capacity c_p | gas | 78.4 J/(mol K) specific heat of formation Δ_fH° | solid | -0.1108 kJ/g molar heat of formation Δ_fH° | solid | -45.6 kJ/mol (at STP)](../image_source/bc3acdb1fd6b4f90de39767b74fef1b1.png)
specific heat capacity c_p | gas | 0.1904 J/(g K) molar heat capacity c_p | gas | 78.4 J/(mol K) specific heat of formation Δ_fH° | solid | -0.1108 kJ/g molar heat of formation Δ_fH° | solid | -45.6 kJ/mol (at STP)
Chemical identifiers
![CAS number | 13455-01-1 PubChem CID number | 83485 PubChem SID number | 24854489 SMILES identifier | P(I)(I)I InChI identifier | InChI=1/I3P/c1-4(2)3 MDL number | MFCD00011442](../image_source/d44a660a3063676b68d8c943dc2a6afc.png)
CAS number | 13455-01-1 PubChem CID number | 83485 PubChem SID number | 24854489 SMILES identifier | P(I)(I)I InChI identifier | InChI=1/I3P/c1-4(2)3 MDL number | MFCD00011442
NFPA label
![NFPA label](../image_source/920d436f9e3c2080c38a4a03ea1e368f.png)
NFPA label
![NFPA health rating | 3 NFPA fire rating | 0 NFPA reactivity rating | 2](../image_source/758d1ac13478791ec04a09124de67bae.png)
NFPA health rating | 3 NFPA fire rating | 0 NFPA reactivity rating | 2