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KOH + MnO2 + KClO = H2O + KMnO4 + KCl

Input interpretation

KOH potassium hydroxide + MnO_2 manganese dioxide + KClO ⟶ H_2O water + KMnO_4 potassium permanganate + KCl potassium chloride
KOH potassium hydroxide + MnO_2 manganese dioxide + KClO ⟶ H_2O water + KMnO_4 potassium permanganate + KCl potassium chloride

Balanced equation

Balance the chemical equation algebraically: KOH + MnO_2 + KClO ⟶ H_2O + KMnO_4 + KCl Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 MnO_2 + c_3 KClO ⟶ c_4 H_2O + c_5 KMnO_4 + c_6 KCl Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Mn and Cl: H: | c_1 = 2 c_4 K: | c_1 + c_3 = c_5 + c_6 O: | c_1 + 2 c_2 + c_3 = c_4 + 4 c_5 Mn: | c_2 = c_5 Cl: | c_3 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 3 c_4 = 1 c_5 = 2 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 KOH + 2 MnO_2 + 3 KClO ⟶ H_2O + 2 KMnO_4 + 3 KCl
Balance the chemical equation algebraically: KOH + MnO_2 + KClO ⟶ H_2O + KMnO_4 + KCl Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 MnO_2 + c_3 KClO ⟶ c_4 H_2O + c_5 KMnO_4 + c_6 KCl Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Mn and Cl: H: | c_1 = 2 c_4 K: | c_1 + c_3 = c_5 + c_6 O: | c_1 + 2 c_2 + c_3 = c_4 + 4 c_5 Mn: | c_2 = c_5 Cl: | c_3 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 3 c_4 = 1 c_5 = 2 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 KOH + 2 MnO_2 + 3 KClO ⟶ H_2O + 2 KMnO_4 + 3 KCl

Structures

 + + KClO ⟶ + +
+ + KClO ⟶ + +

Names

potassium hydroxide + manganese dioxide + KClO ⟶ water + potassium permanganate + potassium chloride
potassium hydroxide + manganese dioxide + KClO ⟶ water + potassium permanganate + potassium chloride

Equilibrium constant

Construct the equilibrium constant, K, expression for: KOH + MnO_2 + KClO ⟶ H_2O + KMnO_4 + KCl Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 KOH + 2 MnO_2 + 3 KClO ⟶ H_2O + 2 KMnO_4 + 3 KCl Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 MnO_2 | 2 | -2 KClO | 3 | -3 H_2O | 1 | 1 KMnO_4 | 2 | 2 KCl | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 2 | -2 | ([KOH])^(-2) MnO_2 | 2 | -2 | ([MnO2])^(-2) KClO | 3 | -3 | ([KClO])^(-3) H_2O | 1 | 1 | [H2O] KMnO_4 | 2 | 2 | ([KMnO4])^2 KCl | 3 | 3 | ([KCl])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([KOH])^(-2) ([MnO2])^(-2) ([KClO])^(-3) [H2O] ([KMnO4])^2 ([KCl])^3 = ([H2O] ([KMnO4])^2 ([KCl])^3)/(([KOH])^2 ([MnO2])^2 ([KClO])^3)
Construct the equilibrium constant, K, expression for: KOH + MnO_2 + KClO ⟶ H_2O + KMnO_4 + KCl Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 KOH + 2 MnO_2 + 3 KClO ⟶ H_2O + 2 KMnO_4 + 3 KCl Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 MnO_2 | 2 | -2 KClO | 3 | -3 H_2O | 1 | 1 KMnO_4 | 2 | 2 KCl | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 2 | -2 | ([KOH])^(-2) MnO_2 | 2 | -2 | ([MnO2])^(-2) KClO | 3 | -3 | ([KClO])^(-3) H_2O | 1 | 1 | [H2O] KMnO_4 | 2 | 2 | ([KMnO4])^2 KCl | 3 | 3 | ([KCl])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-2) ([MnO2])^(-2) ([KClO])^(-3) [H2O] ([KMnO4])^2 ([KCl])^3 = ([H2O] ([KMnO4])^2 ([KCl])^3)/(([KOH])^2 ([MnO2])^2 ([KClO])^3)

Rate of reaction

Construct the rate of reaction expression for: KOH + MnO_2 + KClO ⟶ H_2O + KMnO_4 + KCl Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 KOH + 2 MnO_2 + 3 KClO ⟶ H_2O + 2 KMnO_4 + 3 KCl Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 MnO_2 | 2 | -2 KClO | 3 | -3 H_2O | 1 | 1 KMnO_4 | 2 | 2 KCl | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 2 | -2 | -1/2 (Δ[KOH])/(Δt) MnO_2 | 2 | -2 | -1/2 (Δ[MnO2])/(Δt) KClO | 3 | -3 | -1/3 (Δ[KClO])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) KMnO_4 | 2 | 2 | 1/2 (Δ[KMnO4])/(Δt) KCl | 3 | 3 | 1/3 (Δ[KCl])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/2 (Δ[KOH])/(Δt) = -1/2 (Δ[MnO2])/(Δt) = -1/3 (Δ[KClO])/(Δt) = (Δ[H2O])/(Δt) = 1/2 (Δ[KMnO4])/(Δt) = 1/3 (Δ[KCl])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: KOH + MnO_2 + KClO ⟶ H_2O + KMnO_4 + KCl Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 KOH + 2 MnO_2 + 3 KClO ⟶ H_2O + 2 KMnO_4 + 3 KCl Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 MnO_2 | 2 | -2 KClO | 3 | -3 H_2O | 1 | 1 KMnO_4 | 2 | 2 KCl | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 2 | -2 | -1/2 (Δ[KOH])/(Δt) MnO_2 | 2 | -2 | -1/2 (Δ[MnO2])/(Δt) KClO | 3 | -3 | -1/3 (Δ[KClO])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) KMnO_4 | 2 | 2 | 1/2 (Δ[KMnO4])/(Δt) KCl | 3 | 3 | 1/3 (Δ[KCl])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[KOH])/(Δt) = -1/2 (Δ[MnO2])/(Δt) = -1/3 (Δ[KClO])/(Δt) = (Δ[H2O])/(Δt) = 1/2 (Δ[KMnO4])/(Δt) = 1/3 (Δ[KCl])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | potassium hydroxide | manganese dioxide | KClO | water | potassium permanganate | potassium chloride formula | KOH | MnO_2 | KClO | H_2O | KMnO_4 | KCl Hill formula | HKO | MnO_2 | ClKO | H_2O | KMnO_4 | ClK name | potassium hydroxide | manganese dioxide | | water | potassium permanganate | potassium chloride IUPAC name | potassium hydroxide | dioxomanganese | | water | potassium permanganate | potassium chloride
| potassium hydroxide | manganese dioxide | KClO | water | potassium permanganate | potassium chloride formula | KOH | MnO_2 | KClO | H_2O | KMnO_4 | KCl Hill formula | HKO | MnO_2 | ClKO | H_2O | KMnO_4 | ClK name | potassium hydroxide | manganese dioxide | | water | potassium permanganate | potassium chloride IUPAC name | potassium hydroxide | dioxomanganese | | water | potassium permanganate | potassium chloride

Substance properties

 | potassium hydroxide | manganese dioxide | KClO | water | potassium permanganate | potassium chloride molar mass | 56.105 g/mol | 86.936 g/mol | 90.55 g/mol | 18.015 g/mol | 158.03 g/mol | 74.55 g/mol phase | solid (at STP) | solid (at STP) | | liquid (at STP) | solid (at STP) | solid (at STP) melting point | 406 °C | 535 °C | | 0 °C | 240 °C | 770 °C boiling point | 1327 °C | | | 99.9839 °C | | 1420 °C density | 2.044 g/cm^3 | 5.03 g/cm^3 | | 1 g/cm^3 | 1 g/cm^3 | 1.98 g/cm^3 solubility in water | soluble | insoluble | | | | soluble surface tension | | | | 0.0728 N/m | |  dynamic viscosity | 0.001 Pa s (at 550 °C) | | | 8.9×10^-4 Pa s (at 25 °C) | |  odor | | | | odorless | odorless | odorless
| potassium hydroxide | manganese dioxide | KClO | water | potassium permanganate | potassium chloride molar mass | 56.105 g/mol | 86.936 g/mol | 90.55 g/mol | 18.015 g/mol | 158.03 g/mol | 74.55 g/mol phase | solid (at STP) | solid (at STP) | | liquid (at STP) | solid (at STP) | solid (at STP) melting point | 406 °C | 535 °C | | 0 °C | 240 °C | 770 °C boiling point | 1327 °C | | | 99.9839 °C | | 1420 °C density | 2.044 g/cm^3 | 5.03 g/cm^3 | | 1 g/cm^3 | 1 g/cm^3 | 1.98 g/cm^3 solubility in water | soluble | insoluble | | | | soluble surface tension | | | | 0.0728 N/m | | dynamic viscosity | 0.001 Pa s (at 550 °C) | | | 8.9×10^-4 Pa s (at 25 °C) | | odor | | | | odorless | odorless | odorless

Units