Input interpretation
![sodium tetraborate tetrahydrate | molar mass](../image_source/d4b94633ba282d8e474426d44b0ba2de.png)
sodium tetraborate tetrahydrate | molar mass
Result
![Find the molar mass, M, for sodium tetraborate tetrahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Na_2B_4O_7·4H_2O Use the chemical formula, Na_2B_4O_7·4H_2O, to count the number of atoms, N_i, for each element: | N_i B (boron) | 4 H (hydrogen) | 8 Na (sodium) | 12 O (oxygen) | 16 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 4 | 10.81 H (hydrogen) | 8 | 1.008 Na (sodium) | 12 | 22.98976928 O (oxygen) | 16 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 4 | 10.81 | 4 × 10.81 = 43.24 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 Na (sodium) | 12 | 22.98976928 | 12 × 22.98976928 = 275.87723136 O (oxygen) | 16 | 15.999 | 16 × 15.999 = 255.984 M = 43.24 g/mol + 8.064 g/mol + 275.87723136 g/mol + 255.984 g/mol = 583.17 g/mol](../image_source/4193a334357404dd993077d426874579.png)
Find the molar mass, M, for sodium tetraborate tetrahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Na_2B_4O_7·4H_2O Use the chemical formula, Na_2B_4O_7·4H_2O, to count the number of atoms, N_i, for each element: | N_i B (boron) | 4 H (hydrogen) | 8 Na (sodium) | 12 O (oxygen) | 16 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 4 | 10.81 H (hydrogen) | 8 | 1.008 Na (sodium) | 12 | 22.98976928 O (oxygen) | 16 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 4 | 10.81 | 4 × 10.81 = 43.24 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 Na (sodium) | 12 | 22.98976928 | 12 × 22.98976928 = 275.87723136 O (oxygen) | 16 | 15.999 | 16 × 15.999 = 255.984 M = 43.24 g/mol + 8.064 g/mol + 275.87723136 g/mol + 255.984 g/mol = 583.17 g/mol
Unit conversion
![0.58317 kg/mol (kilograms per mole)](../image_source/ef77395b969674a34a9b23343640ecd0.png)
0.58317 kg/mol (kilograms per mole)
Comparisons
![≈ 0.81 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/9d6e83a586a31956369cc7e049605d2d.png)
≈ 0.81 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 3 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/abddbd2e52f38a1cbf0de62d4ae8af6d.png)
≈ 3 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 10 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/39209ca3d1c583ea4be9c8d5c66226be.png)
≈ 10 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 9.7×10^-22 grams | 9.7×10^-25 kg (kilograms) | 583 u (unified atomic mass units) | 583 Da (daltons)](../image_source/c5f344679861f63db8aa6ce4127a9be7.png)
Mass of a molecule m from m = M/N_A: | 9.7×10^-22 grams | 9.7×10^-25 kg (kilograms) | 583 u (unified atomic mass units) | 583 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 583](../image_source/eb15246a05bb0560ec8771e880ba3550.png)
Relative molecular mass M_r from M_r = M_u/M: | 583