Input interpretation
(4-benzoylbenzyl)trimethylammonium chloride | molar mass
Result
Find the molar mass, M, for (4-benzoylbenzyl)trimethylammonium chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5COC_6H_4CH_2N(CH_3)_3Cl Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 17 Cl (chlorine) | 1 H (hydrogen) | 20 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 17 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 20 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 17 | 12.011 | 17 × 12.011 = 204.187 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 20 | 1.008 | 20 × 1.008 = 20.160 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 204.187 g/mol + 35.45 g/mol + 20.160 g/mol + 14.007 g/mol + 15.999 g/mol = 289.80 g/mol
Unit conversion
0.2898 kg/mol (kilograms per mole)
Comparisons
≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 290 u (unified atomic mass units) | 290 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 290