Input interpretation
![potassium aminetrichloroplatinate(II) | molar mass](../image_source/abe453f849c7aca14f4cdea09d3c97c0.png)
potassium aminetrichloroplatinate(II) | molar mass
Result
![Find the molar mass, M, for potassium aminetrichloroplatinate(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: KPt(NH_3)Cl_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 H (hydrogen) | 3 K (potassium) | 1 N (nitrogen) | 1 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 H (hydrogen) | 3 | 1.008 K (potassium) | 1 | 39.0983 N (nitrogen) | 1 | 14.007 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 K (potassium) | 1 | 39.0983 | 1 × 39.0983 = 39.0983 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 106.35 g/mol + 3.024 g/mol + 39.0983 g/mol + 14.007 g/mol + 195.084 g/mol = 357.56 g/mol](../image_source/78bf66cf94b7858d4d3f191149345c5b.png)
Find the molar mass, M, for potassium aminetrichloroplatinate(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: KPt(NH_3)Cl_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 H (hydrogen) | 3 K (potassium) | 1 N (nitrogen) | 1 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 H (hydrogen) | 3 | 1.008 K (potassium) | 1 | 39.0983 N (nitrogen) | 1 | 14.007 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 K (potassium) | 1 | 39.0983 | 1 × 39.0983 = 39.0983 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 106.35 g/mol + 3.024 g/mol + 39.0983 g/mol + 14.007 g/mol + 195.084 g/mol = 357.56 g/mol
Unit conversion
![0.3576 kg/mol (kilograms per mole)](../image_source/918512b22314d3a4423987b42c2b29a3.png)
0.3576 kg/mol (kilograms per mole)
Comparisons
![≈ 0.5 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/ec481ac0cae893ed14ffc49d38747df7.png)
≈ 0.5 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/a05faf117835a2085af7893e7366fbe9.png)
≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 6.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/bed8893893cdaadefdce2a3c115276a8.png)
≈ 6.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.9×10^-22 grams | 5.9×10^-25 kg (kilograms) | 358 u (unified atomic mass units) | 358 Da (daltons)](../image_source/989f9c9044ba40a31ce3c54bc63c2e04.png)
Mass of a molecule m from m = M/N_A: | 5.9×10^-22 grams | 5.9×10^-25 kg (kilograms) | 358 u (unified atomic mass units) | 358 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 358](../image_source/db9ef61c2d5c038fce3283b96aad74d8.png)
Relative molecular mass M_r from M_r = M_u/M: | 358