molar mass of (S)-(+)-2-(dibenzylamino)-3-phenyl-1-propanol

(S)-(+)-2-(dibenzylamino)-3-phenyl-1-propanol | molar mass

Find the molar mass, M, for (S)-(+)-2-(dibenzylamino)-3-phenyl-1-propanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5CH_2CH[N(CH_2C_6H_5)_2]CH_2OH Use the chemical formula, C_6H_5CH_2CH[N(CH_2C_6H_5)_2]CH_2OH, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 23 H (hydrogen) | 25 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 23 | 12.011 H (hydrogen) | 25 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 23 | 12.011 | 23 × 12.011 = 276.253 H (hydrogen) | 25 | 1.008 | 25 × 1.008 = 25.200 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 276.253 g/mol + 25.200 g/mol + 14.007 g/mol + 15.999 g/mol = 331.459 g/mol

0.33146 kg/mol (kilograms per mole)

≈ 0.46 × molar mass of fullerene ( ≈ 721 g/mol )

≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )

≈ 5.7 × molar mass of sodium chloride ( ≈ 58 g/mol )

Mass of a molecule m from m = M/N_A: | 5.5×10^-22 grams | 5.5×10^-25 kg (kilograms) | 331 u (unified atomic mass units) | 331 Da (daltons)

Relative molecular mass M_r from M_r = M_u/M: | 331