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molar mass of lithium molybdate

Input interpretation

lithium molybdate | molar mass
lithium molybdate | molar mass

Result

Find the molar mass, M, for lithium molybdate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Li_2MoO_4 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Li (lithium) | 2  Mo (molybdenum) | 1  O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Li (lithium) | 2 | 6.94  Mo (molybdenum) | 1 | 95.95  O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Li (lithium) | 2 | 6.94 | 2 × 6.94 = 13.88  Mo (molybdenum) | 1 | 95.95 | 1 × 95.95 = 95.95  O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996  M = 13.88 g/mol + 95.95 g/mol + 63.996 g/mol = 173.83 g/mol
Find the molar mass, M, for lithium molybdate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Li_2MoO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Li (lithium) | 2 Mo (molybdenum) | 1 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Li (lithium) | 2 | 6.94 Mo (molybdenum) | 1 | 95.95 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Li (lithium) | 2 | 6.94 | 2 × 6.94 = 13.88 Mo (molybdenum) | 1 | 95.95 | 1 × 95.95 = 95.95 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 13.88 g/mol + 95.95 g/mol + 63.996 g/mol = 173.83 g/mol

Unit conversion

0.1738 kg/mol (kilograms per mole)
0.1738 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.24 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.24 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.9 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 3 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 3 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 2.9×10^-22 grams  | 2.9×10^-25 kg (kilograms)  | 174 u (unified atomic mass units)  | 174 Da (daltons)
Mass of a molecule m from m = M/N_A: | 2.9×10^-22 grams | 2.9×10^-25 kg (kilograms) | 174 u (unified atomic mass units) | 174 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 174
Relative molecular mass M_r from M_r = M_u/M: | 174