Search

K2MnO4 + HBr = H2O + Br2 + KBr + MnBr2

Input interpretation

K_2MnO_4 potassium manganate + HBr hydrogen bromide ⟶ H_2O water + Br_2 bromine + KBr potassium bromide + MnBr_2 manganese(II) bromide
K_2MnO_4 potassium manganate + HBr hydrogen bromide ⟶ H_2O water + Br_2 bromine + KBr potassium bromide + MnBr_2 manganese(II) bromide

Balanced equation

Balance the chemical equation algebraically: K_2MnO_4 + HBr ⟶ H_2O + Br_2 + KBr + MnBr_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 K_2MnO_4 + c_2 HBr ⟶ c_3 H_2O + c_4 Br_2 + c_5 KBr + c_6 MnBr_2 Set the number of atoms in the reactants equal to the number of atoms in the products for K, Mn, O, Br and H: K: | 2 c_1 = c_5 Mn: | c_1 = c_6 O: | 4 c_1 = c_3 Br: | c_2 = 2 c_4 + c_5 + 2 c_6 H: | c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 8 c_3 = 4 c_4 = 2 c_5 = 2 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | K_2MnO_4 + 8 HBr ⟶ 4 H_2O + 2 Br_2 + 2 KBr + MnBr_2
Balance the chemical equation algebraically: K_2MnO_4 + HBr ⟶ H_2O + Br_2 + KBr + MnBr_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 K_2MnO_4 + c_2 HBr ⟶ c_3 H_2O + c_4 Br_2 + c_5 KBr + c_6 MnBr_2 Set the number of atoms in the reactants equal to the number of atoms in the products for K, Mn, O, Br and H: K: | 2 c_1 = c_5 Mn: | c_1 = c_6 O: | 4 c_1 = c_3 Br: | c_2 = 2 c_4 + c_5 + 2 c_6 H: | c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 8 c_3 = 4 c_4 = 2 c_5 = 2 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | K_2MnO_4 + 8 HBr ⟶ 4 H_2O + 2 Br_2 + 2 KBr + MnBr_2

Structures

+ ⟶ + + +
+ ⟶ + + +

Names

potassium manganate + hydrogen bromide ⟶ water + bromine + potassium bromide + manganese(II) bromide
potassium manganate + hydrogen bromide ⟶ water + bromine + potassium bromide + manganese(II) bromide

Equilibrium constant

Construct the equilibrium constant, K, expression for: K_2MnO_4 + HBr ⟶ H_2O + Br_2 + KBr + MnBr_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: K_2MnO_4 + 8 HBr ⟶ 4 H_2O + 2 Br_2 + 2 KBr + MnBr_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2MnO_4 | 1 | -1 HBr | 8 | -8 H_2O | 4 | 4 Br_2 | 2 | 2 KBr | 2 | 2 MnBr_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression K_2MnO_4 | 1 | -1 | ([K2MnO4])^(-1) HBr | 8 | -8 | ([HBr])^(-8) H_2O | 4 | 4 | ([H2O])^4 Br_2 | 2 | 2 | ([Br2])^2 KBr | 2 | 2 | ([KBr])^2 MnBr_2 | 1 | 1 | [MnBr2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([K2MnO4])^(-1) ([HBr])^(-8) ([H2O])^4 ([Br2])^2 ([KBr])^2 [MnBr2] = (([H2O])^4 ([Br2])^2 ([KBr])^2 [MnBr2])/([K2MnO4] ([HBr])^8)
Construct the equilibrium constant, K, expression for: K_2MnO_4 + HBr ⟶ H_2O + Br_2 + KBr + MnBr_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: K_2MnO_4 + 8 HBr ⟶ 4 H_2O + 2 Br_2 + 2 KBr + MnBr_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2MnO_4 | 1 | -1 HBr | 8 | -8 H_2O | 4 | 4 Br_2 | 2 | 2 KBr | 2 | 2 MnBr_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression K_2MnO_4 | 1 | -1 | ([K2MnO4])^(-1) HBr | 8 | -8 | ([HBr])^(-8) H_2O | 4 | 4 | ([H2O])^4 Br_2 | 2 | 2 | ([Br2])^2 KBr | 2 | 2 | ([KBr])^2 MnBr_2 | 1 | 1 | [MnBr2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([K2MnO4])^(-1) ([HBr])^(-8) ([H2O])^4 ([Br2])^2 ([KBr])^2 [MnBr2] = (([H2O])^4 ([Br2])^2 ([KBr])^2 [MnBr2])/([K2MnO4] ([HBr])^8)

Rate of reaction

Construct the rate of reaction expression for: K_2MnO_4 + HBr ⟶ H_2O + Br_2 + KBr + MnBr_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: K_2MnO_4 + 8 HBr ⟶ 4 H_2O + 2 Br_2 + 2 KBr + MnBr_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2MnO_4 | 1 | -1 HBr | 8 | -8 H_2O | 4 | 4 Br_2 | 2 | 2 KBr | 2 | 2 MnBr_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term K_2MnO_4 | 1 | -1 | -(Δ[K2MnO4])/(Δt) HBr | 8 | -8 | -1/8 (Δ[HBr])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) Br_2 | 2 | 2 | 1/2 (Δ[Br2])/(Δt) KBr | 2 | 2 | 1/2 (Δ[KBr])/(Δt) MnBr_2 | 1 | 1 | (Δ[MnBr2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[K2MnO4])/(Δt) = -1/8 (Δ[HBr])/(Δt) = 1/4 (Δ[H2O])/(Δt) = 1/2 (Δ[Br2])/(Δt) = 1/2 (Δ[KBr])/(Δt) = (Δ[MnBr2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: K_2MnO_4 + HBr ⟶ H_2O + Br_2 + KBr + MnBr_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: K_2MnO_4 + 8 HBr ⟶ 4 H_2O + 2 Br_2 + 2 KBr + MnBr_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2MnO_4 | 1 | -1 HBr | 8 | -8 H_2O | 4 | 4 Br_2 | 2 | 2 KBr | 2 | 2 MnBr_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term K_2MnO_4 | 1 | -1 | -(Δ[K2MnO4])/(Δt) HBr | 8 | -8 | -1/8 (Δ[HBr])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) Br_2 | 2 | 2 | 1/2 (Δ[Br2])/(Δt) KBr | 2 | 2 | 1/2 (Δ[KBr])/(Δt) MnBr_2 | 1 | 1 | (Δ[MnBr2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[K2MnO4])/(Δt) = -1/8 (Δ[HBr])/(Δt) = 1/4 (Δ[H2O])/(Δt) = 1/2 (Δ[Br2])/(Δt) = 1/2 (Δ[KBr])/(Δt) = (Δ[MnBr2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| potassium manganate | hydrogen bromide | water | bromine | potassium bromide | manganese(II) bromide formula | K_2MnO_4 | HBr | H_2O | Br_2 | KBr | MnBr_2 Hill formula | K_2MnO_4 | BrH | H_2O | Br_2 | BrK | Br_2Mn name | potassium manganate | hydrogen bromide | water | bromine | potassium bromide | manganese(II) bromide IUPAC name | dipotassium dioxido-dioxomanganese | hydrogen bromide | water | molecular bromine | potassium bromide | dibromomanganese
| potassium manganate | hydrogen bromide | water | bromine | potassium bromide | manganese(II) bromide formula | K_2MnO_4 | HBr | H_2O | Br_2 | KBr | MnBr_2 Hill formula | K_2MnO_4 | BrH | H_2O | Br_2 | BrK | Br_2Mn name | potassium manganate | hydrogen bromide | water | bromine | potassium bromide | manganese(II) bromide IUPAC name | dipotassium dioxido-dioxomanganese | hydrogen bromide | water | molecular bromine | potassium bromide | dibromomanganese

Random Queries

discoverers of non-metallic elements
atomic diameter of iron vs manganese
molar mass of dichlorofluoromethane
dielectric constant of hydrogen
IUPAC name of fluorine
bonding characteristics of thulium
atomic number of Ge-59 vs Pr-138
chemical types of ammonium bichromate vs sodium trimethylsilanolate
CAS number of strontium sulfide
CAS number of 3-(trifluoromethyl)phenethylamine hydrochloride