Input interpretation
![vanadium trihydroxide | molar mass](../image_source/06e9524b98ecc630ce33c5a8ff669843.png)
vanadium trihydroxide | molar mass
Result
![Find the molar mass, M, for vanadium trihydroxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: V(OH)_3 Use the chemical formula, V(OH)_3, to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 3 O (oxygen) | 3 V (vanadium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 3 | 1.008 O (oxygen) | 3 | 15.999 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 M = 3.024 g/mol + 47.997 g/mol + 50.9415 g/mol = 101.963 g/mol](../image_source/56650a40f49bcabe71f42ac4d53194e3.png)
Find the molar mass, M, for vanadium trihydroxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: V(OH)_3 Use the chemical formula, V(OH)_3, to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 3 O (oxygen) | 3 V (vanadium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 3 | 1.008 O (oxygen) | 3 | 15.999 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 M = 3.024 g/mol + 47.997 g/mol + 50.9415 g/mol = 101.963 g/mol
Unit conversion
![0.10196 kg/mol (kilograms per mole)](../image_source/63ddc245e88eb3fd13c49e3e134b0662.png)
0.10196 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/704ea390e0f0271fabe8429c709eb5cb.png)
≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.53 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/beeff0063991c460fc1fab3dcc210e16.png)
≈ 0.53 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/311e3ad33d02940d7407e8c9faa544e5.png)
≈ 1.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 102 u (unified atomic mass units) | 102 Da (daltons)](../image_source/3ce87d7f25f8ba0397a26be764dc7a58.png)
Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 102 u (unified atomic mass units) | 102 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 102](../image_source/23fdcb3409872ca5a6fde8c55990ab40.png)
Relative molecular mass M_r from M_r = M_u/M: | 102