Input interpretation
![ruthenium(IV) oxide hydrate | molar mass](../image_source/2f8ed8f509b1222094f19971962c495d.png)
ruthenium(IV) oxide hydrate | molar mass
Result
![Find the molar mass, M, for ruthenium(IV) oxide hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: RuO_2·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 2 O (oxygen) | 3 Ru (ruthenium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 2 | 1.008 O (oxygen) | 3 | 15.999 Ru (ruthenium) | 1 | 101.07 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Ru (ruthenium) | 1 | 101.07 | 1 × 101.07 = 101.07 M = 2.016 g/mol + 47.997 g/mol + 101.07 g/mol = 151.08 g/mol](../image_source/f21dd0340141208f8fcc089a531515f2.png)
Find the molar mass, M, for ruthenium(IV) oxide hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: RuO_2·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 2 O (oxygen) | 3 Ru (ruthenium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 2 | 1.008 O (oxygen) | 3 | 15.999 Ru (ruthenium) | 1 | 101.07 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Ru (ruthenium) | 1 | 101.07 | 1 × 101.07 = 101.07 M = 2.016 g/mol + 47.997 g/mol + 101.07 g/mol = 151.08 g/mol
Unit conversion
![0.15108 kg/mol (kilograms per mole)](../image_source/23d2e0af45cc1ca9bfdf99b0d2957439.png)
0.15108 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.21 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/4afe7b4f9fa57ea2a9716f817b19adc2.png)
≈ ( 0.21 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.78 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/56394e296e16e9d59a7d77d790cd68ad.png)
≈ 0.78 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.6 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/655bf7d370fb8385a5573e929970ce2c.png)
≈ 2.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.5×10^-22 grams | 2.5×10^-25 kg (kilograms) | 151 u (unified atomic mass units) | 151 Da (daltons)](../image_source/f4d321f8839ad9a31fbb7e1f497750ff.png)
Mass of a molecule m from m = M/N_A: | 2.5×10^-22 grams | 2.5×10^-25 kg (kilograms) | 151 u (unified atomic mass units) | 151 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 151](../image_source/c19b631b1eb7a20d953a56c74d40ff74.png)
Relative molecular mass M_r from M_r = M_u/M: | 151