Input interpretation
O_2 oxygen + Bi_2S_3 bismuth sulfide ⟶ SO_2 sulfur dioxide + Bi_2O_3 bismuth trioxide
Balanced equation
Balance the chemical equation algebraically: O_2 + Bi_2S_3 ⟶ SO_2 + Bi_2O_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 O_2 + c_2 Bi_2S_3 ⟶ c_3 SO_2 + c_4 Bi_2O_3 Set the number of atoms in the reactants equal to the number of atoms in the products for O, Bi and S: O: | 2 c_1 = 2 c_3 + 3 c_4 Bi: | 2 c_2 = 2 c_4 S: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 9/2 c_2 = 1 c_3 = 3 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 9 c_2 = 2 c_3 = 6 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 9 O_2 + 2 Bi_2S_3 ⟶ 6 SO_2 + 2 Bi_2O_3
Structures
+ ⟶ +
Names
oxygen + bismuth sulfide ⟶ sulfur dioxide + bismuth trioxide