Input interpretation
![2-(9 H-carbazol-9-yl)ethyl acrylate | molar mass](../image_source/cb5d6c59da27264b0612b9f52cafd078.png)
2-(9 H-carbazol-9-yl)ethyl acrylate | molar mass
Result
![Find the molar mass, M, for 2-(9 H-carbazol-9-yl)ethyl acrylate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_17H_15NO_2 Use the chemical formula, C_17H_15NO_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 17 H (hydrogen) | 15 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 17 | 12.011 H (hydrogen) | 15 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 17 | 12.011 | 17 × 12.011 = 204.187 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 204.187 g/mol + 15.120 g/mol + 14.007 g/mol + 31.998 g/mol = 265.312 g/mol](../image_source/c9afb9c0d84024fe90b75d5176412cd7.png)
Find the molar mass, M, for 2-(9 H-carbazol-9-yl)ethyl acrylate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_17H_15NO_2 Use the chemical formula, C_17H_15NO_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 17 H (hydrogen) | 15 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 17 | 12.011 H (hydrogen) | 15 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 17 | 12.011 | 17 × 12.011 = 204.187 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 204.187 g/mol + 15.120 g/mol + 14.007 g/mol + 31.998 g/mol = 265.312 g/mol
Unit conversion
![0.26531 kg/mol (kilograms per mole)](../image_source/ece66463daeb67333560fbc7aefaf8cf.png)
0.26531 kg/mol (kilograms per mole)
Comparisons
![≈ 0.37 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/3240ddca94c910f2054b2a74600421b3.png)
≈ 0.37 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/d85689c197b32edefa6b8e1ae4f198e0.png)
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/fa94a63d099b7a25c5c0621f2ce2223b.png)
≈ 4.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.4×10^-22 grams | 4.4×10^-25 kg (kilograms) | 265 u (unified atomic mass units) | 265 Da (daltons)](../image_source/3258461ab59d4c80c0d5d5c5a0f6f99c.png)
Mass of a molecule m from m = M/N_A: | 4.4×10^-22 grams | 4.4×10^-25 kg (kilograms) | 265 u (unified atomic mass units) | 265 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 265](../image_source/0eb1e24bc5ccc1eaf89ff452b802f993.png)
Relative molecular mass M_r from M_r = M_u/M: | 265