Input interpretation
uroporphyrinogen-iii | molar mass
Result
Find the molar mass, M, for uroporphyrinogen-iii: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_40H_44N_4O_16 Use the chemical formula, C_40H_44N_4O_16, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 40 H (hydrogen) | 36 N (nitrogen) | 4 O (oxygen) | 16 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 40 | 12.011 H (hydrogen) | 36 | 1.008 N (nitrogen) | 4 | 14.007 O (oxygen) | 16 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 40 | 12.011 | 40 × 12.011 = 480.440 H (hydrogen) | 36 | 1.008 | 36 × 1.008 = 36.288 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 O (oxygen) | 16 | 15.999 | 16 × 15.999 = 255.984 M = 480.440 g/mol + 36.288 g/mol + 56.028 g/mol + 255.984 g/mol = 828.740 g/mol
Unit conversion
0.8287 kg/mol (kilograms per mole)
Comparisons
≈ 1.2 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 4.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 14 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1.4×10^-21 grams | 1.4×10^-24 kg (kilograms) | 829 u (unified atomic mass units) | 829 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 829