Input interpretation
(+/-)-sodium camphorsulfonate | molar mass
Result
Find the molar mass, M, for (+/-)-sodium camphorsulfonate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_10H_15NaO_4S Use the chemical formula, C_10H_15NaO_4S, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 10 H (hydrogen) | 15 Na (sodium) | 1 O (oxygen) | 4 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 10 | 12.011 H (hydrogen) | 15 | 1.008 Na (sodium) | 1 | 22.98976928 O (oxygen) | 4 | 15.999 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 120.110 g/mol + 15.120 g/mol + 22.98976928 g/mol + 63.996 g/mol + 32.06 g/mol = 254.28 g/mol
Unit conversion
0.25428 kg/mol (kilograms per mole)
Comparisons
≈ 0.35 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 4.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 4.2×10^-22 grams | 4.2×10^-25 kg (kilograms) | 254 u (unified atomic mass units) | 254 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 254