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relative molecular mass of sodium hexafluoroantimonate

Input interpretation

sodium hexafluoroantimonate | relative molecular mass
sodium hexafluoroantimonate | relative molecular mass

Result

Find the relative molecular mass, M_r, for sodium hexafluoroantimonate: M_r = sum _iN_im_i/m_u Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NaSbF_6 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  F (fluorine) | 6  Na (sodium) | 1  Sb (antimony) | 1 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table. Since m_i is divided by the atomic mass constant, m_u, the result is a unitless relative atomic mass:  | N_i | m_i/m_u  F (fluorine) | 6 | 18.998403163  Na (sodium) | 1 | 22.98976928  Sb (antimony) | 1 | 121.760 Multiply N_i by m_i/m_u to compute the relative mass for each element. Then sum those values to compute the relative molecular mass, M_r: Answer: |   | | N_i | m_i/m_u | relative mass  F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978  Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928  Sb (antimony) | 1 | 121.760 | 1 × 121.760 = 121.760  M_r = 113.990418978 + 22.98976928 + 121.760 = 258.740
Find the relative molecular mass, M_r, for sodium hexafluoroantimonate: M_r = sum _iN_im_i/m_u Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NaSbF_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 6 Na (sodium) | 1 Sb (antimony) | 1 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table. Since m_i is divided by the atomic mass constant, m_u, the result is a unitless relative atomic mass: | N_i | m_i/m_u F (fluorine) | 6 | 18.998403163 Na (sodium) | 1 | 22.98976928 Sb (antimony) | 1 | 121.760 Multiply N_i by m_i/m_u to compute the relative mass for each element. Then sum those values to compute the relative molecular mass, M_r: Answer: | | | N_i | m_i/m_u | relative mass F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 Sb (antimony) | 1 | 121.760 | 1 × 121.760 = 121.760 M_r = 113.990418978 + 22.98976928 + 121.760 = 258.740

Comparisons

 ≈ 0.36 × relative molecular mass of fullerene ( ≈ 721 )
≈ 0.36 × relative molecular mass of fullerene ( ≈ 721 )
 ≈ 1.3 × relative molecular mass of caffeine ( ≈ 194 )
≈ 1.3 × relative molecular mass of caffeine ( ≈ 194 )
 ≈ 4.4 × relative molecular mass of sodium chloride ( ≈ 58 )
≈ 4.4 × relative molecular mass of sodium chloride ( ≈ 58 )

Corresponding quantities

Molar mass M from M = M_uM_r:  | 259 g/mol (grams per mole)
Molar mass M from M = M_uM_r: | 259 g/mol (grams per mole)
Molecular mass m from m = M_rM_u/N_A:  | 4.3×10^-22 grams  | 4.3×10^-25 kg (kilograms)
Molecular mass m from m = M_rM_u/N_A: | 4.3×10^-22 grams | 4.3×10^-25 kg (kilograms)