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H2 + FeS = Fe + H2S

Input interpretation

H_2 hydrogen + FeS ferrous sulfide ⟶ Fe iron + H_2S hydrogen sulfide
H_2 hydrogen + FeS ferrous sulfide ⟶ Fe iron + H_2S hydrogen sulfide

Balanced equation

Balance the chemical equation algebraically: H_2 + FeS ⟶ Fe + H_2S Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 FeS ⟶ c_3 Fe + c_4 H_2S Set the number of atoms in the reactants equal to the number of atoms in the products for H, Fe and S: H: | 2 c_1 = 2 c_4 Fe: | c_2 = c_3 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | H_2 + FeS ⟶ Fe + H_2S
Balance the chemical equation algebraically: H_2 + FeS ⟶ Fe + H_2S Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 FeS ⟶ c_3 Fe + c_4 H_2S Set the number of atoms in the reactants equal to the number of atoms in the products for H, Fe and S: H: | 2 c_1 = 2 c_4 Fe: | c_2 = c_3 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2 + FeS ⟶ Fe + H_2S

Structures

 + ⟶ +
+ ⟶ +

Names

hydrogen + ferrous sulfide ⟶ iron + hydrogen sulfide
hydrogen + ferrous sulfide ⟶ iron + hydrogen sulfide

Reaction thermodynamics

Enthalpy

 | hydrogen | ferrous sulfide | iron | hydrogen sulfide molecular enthalpy | 0 kJ/mol | -100 kJ/mol | 0 kJ/mol | -20.6 kJ/mol total enthalpy | 0 kJ/mol | -100 kJ/mol | 0 kJ/mol | -20.6 kJ/mol  | H_initial = -100 kJ/mol | | H_final = -20.6 kJ/mol |  ΔH_rxn^0 | -20.6 kJ/mol - -100 kJ/mol = 79.4 kJ/mol (endothermic) | | |
| hydrogen | ferrous sulfide | iron | hydrogen sulfide molecular enthalpy | 0 kJ/mol | -100 kJ/mol | 0 kJ/mol | -20.6 kJ/mol total enthalpy | 0 kJ/mol | -100 kJ/mol | 0 kJ/mol | -20.6 kJ/mol | H_initial = -100 kJ/mol | | H_final = -20.6 kJ/mol | ΔH_rxn^0 | -20.6 kJ/mol - -100 kJ/mol = 79.4 kJ/mol (endothermic) | | |

Entropy

 | hydrogen | ferrous sulfide | iron | hydrogen sulfide molecular entropy | 115 J/(mol K) | 67 J/(mol K) | 27 J/(mol K) | 206 J/(mol K) total entropy | 115 J/(mol K) | 67 J/(mol K) | 27 J/(mol K) | 206 J/(mol K)  | S_initial = 182 J/(mol K) | | S_final = 233 J/(mol K) |  ΔS_rxn^0 | 233 J/(mol K) - 182 J/(mol K) = 51 J/(mol K) (endoentropic) | | |
| hydrogen | ferrous sulfide | iron | hydrogen sulfide molecular entropy | 115 J/(mol K) | 67 J/(mol K) | 27 J/(mol K) | 206 J/(mol K) total entropy | 115 J/(mol K) | 67 J/(mol K) | 27 J/(mol K) | 206 J/(mol K) | S_initial = 182 J/(mol K) | | S_final = 233 J/(mol K) | ΔS_rxn^0 | 233 J/(mol K) - 182 J/(mol K) = 51 J/(mol K) (endoentropic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2 + FeS ⟶ Fe + H_2S Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2 + FeS ⟶ Fe + H_2S Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 1 | -1 FeS | 1 | -1 Fe | 1 | 1 H_2S | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 1 | -1 | ([H2])^(-1) FeS | 1 | -1 | ([FeS])^(-1) Fe | 1 | 1 | [Fe] H_2S | 1 | 1 | [H2S] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([H2])^(-1) ([FeS])^(-1) [Fe] [H2S] = ([Fe] [H2S])/([H2] [FeS])
Construct the equilibrium constant, K, expression for: H_2 + FeS ⟶ Fe + H_2S Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2 + FeS ⟶ Fe + H_2S Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 1 | -1 FeS | 1 | -1 Fe | 1 | 1 H_2S | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 1 | -1 | ([H2])^(-1) FeS | 1 | -1 | ([FeS])^(-1) Fe | 1 | 1 | [Fe] H_2S | 1 | 1 | [H2S] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2])^(-1) ([FeS])^(-1) [Fe] [H2S] = ([Fe] [H2S])/([H2] [FeS])

Rate of reaction

Construct the rate of reaction expression for: H_2 + FeS ⟶ Fe + H_2S Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2 + FeS ⟶ Fe + H_2S Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 1 | -1 FeS | 1 | -1 Fe | 1 | 1 H_2S | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 1 | -1 | -(Δ[H2])/(Δt) FeS | 1 | -1 | -(Δ[FeS])/(Δt) Fe | 1 | 1 | (Δ[Fe])/(Δt) H_2S | 1 | 1 | (Δ[H2S])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[H2])/(Δt) = -(Δ[FeS])/(Δt) = (Δ[Fe])/(Δt) = (Δ[H2S])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2 + FeS ⟶ Fe + H_2S Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2 + FeS ⟶ Fe + H_2S Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 1 | -1 FeS | 1 | -1 Fe | 1 | 1 H_2S | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 1 | -1 | -(Δ[H2])/(Δt) FeS | 1 | -1 | -(Δ[FeS])/(Δt) Fe | 1 | 1 | (Δ[Fe])/(Δt) H_2S | 1 | 1 | (Δ[H2S])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2])/(Δt) = -(Δ[FeS])/(Δt) = (Δ[Fe])/(Δt) = (Δ[H2S])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | hydrogen | ferrous sulfide | iron | hydrogen sulfide formula | H_2 | FeS | Fe | H_2S name | hydrogen | ferrous sulfide | iron | hydrogen sulfide IUPAC name | molecular hydrogen | | iron | hydrogen sulfide
| hydrogen | ferrous sulfide | iron | hydrogen sulfide formula | H_2 | FeS | Fe | H_2S name | hydrogen | ferrous sulfide | iron | hydrogen sulfide IUPAC name | molecular hydrogen | | iron | hydrogen sulfide

Substance properties

 | hydrogen | ferrous sulfide | iron | hydrogen sulfide molar mass | 2.016 g/mol | 87.9 g/mol | 55.845 g/mol | 34.08 g/mol phase | gas (at STP) | solid (at STP) | solid (at STP) | gas (at STP) melting point | -259.2 °C | 1195 °C | 1535 °C | -85 °C boiling point | -252.8 °C | | 2750 °C | -60 °C density | 8.99×10^-5 g/cm^3 (at 0 °C) | 4.84 g/cm^3 | 7.874 g/cm^3 | 0.001393 g/cm^3 (at 25 °C) solubility in water | | insoluble | insoluble |  dynamic viscosity | 8.9×10^-6 Pa s (at 25 °C) | 0.00343 Pa s (at 1250 °C) | | 1.239×10^-5 Pa s (at 25 °C) odor | odorless | | |
| hydrogen | ferrous sulfide | iron | hydrogen sulfide molar mass | 2.016 g/mol | 87.9 g/mol | 55.845 g/mol | 34.08 g/mol phase | gas (at STP) | solid (at STP) | solid (at STP) | gas (at STP) melting point | -259.2 °C | 1195 °C | 1535 °C | -85 °C boiling point | -252.8 °C | | 2750 °C | -60 °C density | 8.99×10^-5 g/cm^3 (at 0 °C) | 4.84 g/cm^3 | 7.874 g/cm^3 | 0.001393 g/cm^3 (at 25 °C) solubility in water | | insoluble | insoluble | dynamic viscosity | 8.9×10^-6 Pa s (at 25 °C) | 0.00343 Pa s (at 1250 °C) | | 1.239×10^-5 Pa s (at 25 °C) odor | odorless | | |

Units