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molar mass of 2-(1,3-dioxolan-2-yl)ethyltriphenylphosphonium bromide

Input interpretation

2-(1, 3-dioxolan-2-yl)ethyltriphenylphosphonium bromide | molar mass
2-(1, 3-dioxolan-2-yl)ethyltriphenylphosphonium bromide | molar mass

Result

Find the molar mass, M, for 2-(1, 3-dioxolan-2-yl)ethyltriphenylphosphonium bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_23H_24BrO_2P Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Br (bromine) | 1  O (oxygen) | 2  C (carbon) | 23  P (phosphorus) | 1  H (hydrogen) | 24 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Br (bromine) | 1 | 79.904  O (oxygen) | 2 | 15.999  C (carbon) | 23 | 12.011  P (phosphorus) | 1 | 30.973761998  H (hydrogen) | 24 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904  O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998  C (carbon) | 23 | 12.011 | 23 × 12.011 = 276.253  P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998  H (hydrogen) | 24 | 1.008 | 24 × 1.008 = 24.192  M = 79.904 g/mol + 31.998 g/mol + 276.253 g/mol + 30.973761998 g/mol + 24.192 g/mol = 443.321 g/mol
Find the molar mass, M, for 2-(1, 3-dioxolan-2-yl)ethyltriphenylphosphonium bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_23H_24BrO_2P Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 O (oxygen) | 2 C (carbon) | 23 P (phosphorus) | 1 H (hydrogen) | 24 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 O (oxygen) | 2 | 15.999 C (carbon) | 23 | 12.011 P (phosphorus) | 1 | 30.973761998 H (hydrogen) | 24 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 C (carbon) | 23 | 12.011 | 23 × 12.011 = 276.253 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 H (hydrogen) | 24 | 1.008 | 24 × 1.008 = 24.192 M = 79.904 g/mol + 31.998 g/mol + 276.253 g/mol + 30.973761998 g/mol + 24.192 g/mol = 443.321 g/mol

Unit conversion

0.4433 kg/mol (kilograms per mole)
0.4433 kg/mol (kilograms per mole)

Comparisons

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≈ 0.62 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 7.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 7.6 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 7.4×10^-22 grams  | 7.4×10^-25 kg (kilograms)  | 443 u (unified atomic mass units)  | 443 Da (daltons)
Mass of a molecule m from m = M/N_A: | 7.4×10^-22 grams | 7.4×10^-25 kg (kilograms) | 443 u (unified atomic mass units) | 443 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 443
Relative molecular mass M_r from M_r = M_u/M: | 443