Input interpretation
![1, 2-diiodoethane](../image_source/672bdf2470a3bebd2eeb279daf20d940.png)
1, 2-diiodoethane
Chemical names and formulas
![formula | ICH_2CH_2I Hill formula | C_2H_4I_2 name | 1, 2-diiodoethane alternate names | diiodoethane | ethane, 1, 2-diiodo- | ethylene diiodide | ethylene iodide mass fractions | C (carbon) 8.52% | H (hydrogen) 1.43% | I (iodine) 90%](../image_source/5bc0f6945d7327d78bf3406a60c348dc.png)
formula | ICH_2CH_2I Hill formula | C_2H_4I_2 name | 1, 2-diiodoethane alternate names | diiodoethane | ethane, 1, 2-diiodo- | ethylene diiodide | ethylene iodide mass fractions | C (carbon) 8.52% | H (hydrogen) 1.43% | I (iodine) 90%
Lewis structure
![Draw the Lewis structure of 1, 2-diiodoethane. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), and iodine (n_I, val = 7) atoms: 2 n_C, val + 4 n_H, val + 2 n_I, val = 26 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), and iodine (n_I, full = 8): 2 n_C, full + 4 n_H, full + 2 n_I, full = 40 Subtracting these two numbers shows that 40 - 26 = 14 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 7 bonds and hence 14 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 26 - 14 = 12 electrons left to draw: Answer: | |](../image_source/1b73bd895f044955fe20b0d545636f9d.png)
Draw the Lewis structure of 1, 2-diiodoethane. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), and iodine (n_I, val = 7) atoms: 2 n_C, val + 4 n_H, val + 2 n_I, val = 26 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), and iodine (n_I, full = 8): 2 n_C, full + 4 n_H, full + 2 n_I, full = 40 Subtracting these two numbers shows that 40 - 26 = 14 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 7 bonds and hence 14 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 26 - 14 = 12 electrons left to draw: Answer: | |
3D structure
![3D structure](../image_source/f2dfd1934ed4c92e928a33297d0b94d8.png)
3D structure
Basic properties
![molar mass | 281.863 g/mol phase | solid (at STP) melting point | 81 °C boiling point | 206 °C density | 2.132 g/cm^3 solubility in water | insoluble](../image_source/2c1ef76ae1802cab571479b75c8e9939.png)
molar mass | 281.863 g/mol phase | solid (at STP) melting point | 81 °C boiling point | 206 °C density | 2.132 g/cm^3 solubility in water | insoluble
Units
Solid properties (at STP)
![density | 2.132 g/cm^3 vapor pressure | 0.08 mmHg (at 16 °C) refractive index | 1.871](../image_source/5fe3505bcae36841682cab1b7e65f3b4.png)
density | 2.132 g/cm^3 vapor pressure | 0.08 mmHg (at 16 °C) refractive index | 1.871
Units
Thermodynamic properties
![specific heat of formation Δ_fH° | gas | 0.2661 kJ/g | solid | 0.03299 kJ/g molar heat of formation Δ_fH° | gas | 75 kJ/mol | solid | 9.3 kJ/mol molar heat of vaporization | 49.8 kJ/mol | specific heat of vaporization | 0.177 kJ/g | molar heat of combustion | 1368 kJ/mol | specific heat of combustion | 4.853 kJ/g | molar heat of fusion | 14.2 kJ/mol | specific heat of fusion | 0.05038 kJ/g | (at STP)](../image_source/b96b509cf2440edbbf50e1f196d91049.png)
specific heat of formation Δ_fH° | gas | 0.2661 kJ/g | solid | 0.03299 kJ/g molar heat of formation Δ_fH° | gas | 75 kJ/mol | solid | 9.3 kJ/mol molar heat of vaporization | 49.8 kJ/mol | specific heat of vaporization | 0.177 kJ/g | molar heat of combustion | 1368 kJ/mol | specific heat of combustion | 4.853 kJ/g | molar heat of fusion | 14.2 kJ/mol | specific heat of fusion | 0.05038 kJ/g | (at STP)
Chemical identifiers
![CAS number | 624-73-7 Beilstein number | 1730870 PubChem CID number | 12224 PubChem SID number | 24893381 SMILES identifier | C(CI)I InChI identifier | InChI=1/C2H4I2/c3-1-2-4/h1-2H2 MDL number | MFCD00001093](../image_source/e5ac21390d7eeedeb28ed164ed9b86ea.png)
CAS number | 624-73-7 Beilstein number | 1730870 PubChem CID number | 12224 PubChem SID number | 24893381 SMILES identifier | C(CI)I InChI identifier | InChI=1/C2H4I2/c3-1-2-4/h1-2H2 MDL number | MFCD00001093
Safety properties
![flash point | 101 °C](../image_source/2f765a60ed496e7d46abd71115fd950f.png)
flash point | 101 °C