Input interpretation
1, 13-tetradecadiene | molar mass
Result
Find the molar mass, M, for 1, 13-tetradecadiene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_2=CH(CH_2)_10CH=CH_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 14 H (hydrogen) | 26 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 14 | 12.011 H (hydrogen) | 26 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154 H (hydrogen) | 26 | 1.008 | 26 × 1.008 = 26.208 M = 168.154 g/mol + 26.208 g/mol = 194.362 g/mol
Unit conversion
0.19436 kg/mol (kilograms per mole)
Comparisons
≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.0009 × molar mass of caffeine ( ≈ 194.191 g/mol )
≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 194 u (unified atomic mass units) | 194 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 194