Input interpretation
![aluminum phosphate trihydroxide | molar mass](../image_source/1422564979c09cd82a61b9b9a57847dc.png)
aluminum phosphate trihydroxide | molar mass
Result
![Find the molar mass, M, for aluminum phosphate trihydroxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Al_2(OH_3)_3PO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Al (aluminum) | 1 H (hydrogen) | 6 O (oxygen) | 7 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 H (hydrogen) | 6 | 1.008 O (oxygen) | 7 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 | 1 × 26.9815385 = 26.9815385 H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 26.9815385 g/mol + 6.048 g/mol + 111.993 g/mol + 30.973761998 g/mol = 175.996 g/mol](../image_source/5df8b5acbec6219e26348fbb4d880ab2.png)
Find the molar mass, M, for aluminum phosphate trihydroxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Al_2(OH_3)_3PO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Al (aluminum) | 1 H (hydrogen) | 6 O (oxygen) | 7 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 H (hydrogen) | 6 | 1.008 O (oxygen) | 7 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 | 1 × 26.9815385 = 26.9815385 H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 26.9815385 g/mol + 6.048 g/mol + 111.993 g/mol + 30.973761998 g/mol = 175.996 g/mol
Unit conversion
![0.176 kg/mol (kilograms per mole)](../image_source/22cd4a02bfbbbe98d897c1da7afe8b1c.png)
0.176 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.24 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/381d1beb129fb376bb6c64ffcf1e94d2.png)
≈ ( 0.24 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.91 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/ba4e45718b7f63e515cbcf8c8ef7e2f8.png)
≈ 0.91 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/9ba5c1b254e5876286573dc736bf5a4a.png)
≈ 3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.9×10^-22 grams | 2.9×10^-25 kg (kilograms) | 176 u (unified atomic mass units) | 176 Da (daltons)](../image_source/b0ff48956efe73a160150b57e91c0edd.png)
Mass of a molecule m from m = M/N_A: | 2.9×10^-22 grams | 2.9×10^-25 kg (kilograms) | 176 u (unified atomic mass units) | 176 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 176](../image_source/5d664c14bc7926fa0c1092cfb43f5c38.png)
Relative molecular mass M_r from M_r = M_u/M: | 176