Input interpretation
water + nitric acid + white phosphorus ⟶ nitric oxide + phosphoric acid
Balanced equation
Balance the chemical equation algebraically: + + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, N and P: H: | 2 c_1 + c_2 = 3 c_5 O: | c_1 + 3 c_2 = c_4 + 4 c_5 N: | c_2 = c_4 P: | 4 c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 8/3 c_2 = 20/3 c_3 = 1 c_4 = 20/3 c_5 = 4 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 8 c_2 = 20 c_3 = 3 c_4 = 20 c_5 = 12 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 8 + 20 + 3 ⟶ 20 + 12
Structures
+ + ⟶ +
Names
water + nitric acid + white phosphorus ⟶ nitric oxide + phosphoric acid
Chemical names and formulas
| water | nitric acid | white phosphorus | nitric oxide | phosphoric acid Hill formula | H_2O | HNO_3 | P_4 | NO | H_3O_4P name | water | nitric acid | white phosphorus | nitric oxide | phosphoric acid IUPAC name | water | nitric acid | tetraphosphorus | nitric oxide | phosphoric acid