Input interpretation
nitric acid + bismuth ⟶ water + nitric oxide + Bi(NO3)3
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + Bi(NO3)3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Bi(NO3)3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O and Bi: H: | c_1 = 2 c_3 N: | c_1 = c_4 + 3 c_5 O: | 3 c_1 = c_3 + c_4 + 9 c_5 Bi: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 2 c_4 = 1 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + ⟶ 2 + + Bi(NO3)3
Structures
+ ⟶ + + Bi(NO3)3
Names
nitric acid + bismuth ⟶ water + nitric oxide + Bi(NO3)3
Chemical names and formulas
| nitric acid | bismuth | water | nitric oxide | Bi(NO3)3 formula | | | | | Bi(NO3)3 Hill formula | HNO_3 | Bi | H_2O | NO | BiN3O9 name | nitric acid | bismuth | water | nitric oxide |
Substance properties
| nitric acid | bismuth | water | nitric oxide | Bi(NO3)3 molar mass | 63.012 g/mol | 208.9804 g/mol | 18.015 g/mol | 30.006 g/mol | 394.99 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) | gas (at STP) | melting point | -41.6 °C | 271 °C | 0 °C | -163.6 °C | boiling point | 83 °C | 1560 °C | 99.9839 °C | -151.7 °C | density | 1.5129 g/cm^3 | 9.8 g/cm^3 | 1 g/cm^3 | 0.001226 g/cm^3 (at 25 °C) | solubility in water | miscible | insoluble | | | surface tension | | | 0.0728 N/m | | dynamic viscosity | 7.6×10^-4 Pa s (at 25 °C) | 1.19×10^-4 Pa s (at 500 °C) | 8.9×10^-4 Pa s (at 25 °C) | 1.911×10^-5 Pa s (at 25 °C) | odor | | | odorless | |
Units
