Input interpretation
![sodium permanganate | molar mass](../image_source/54fe838766a4a92f3ec60464451c490e.png)
sodium permanganate | molar mass
Result
![Find the molar mass, M, for sodium permanganate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NaMnO_4 Use the chemical formula, NaMnO_4, to count the number of atoms, N_i, for each element: | N_i Mn (manganese) | 1 Na (sodium) | 1 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Mn (manganese) | 1 | 54.938044 Na (sodium) | 1 | 22.98976928 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Mn (manganese) | 1 | 54.938044 | 1 × 54.938044 = 54.938044 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 54.938044 g/mol + 22.98976928 g/mol + 63.996 g/mol = 141.924 g/mol](../image_source/3f5e83926879198ec7330747a4298904.png)
Find the molar mass, M, for sodium permanganate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NaMnO_4 Use the chemical formula, NaMnO_4, to count the number of atoms, N_i, for each element: | N_i Mn (manganese) | 1 Na (sodium) | 1 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Mn (manganese) | 1 | 54.938044 Na (sodium) | 1 | 22.98976928 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Mn (manganese) | 1 | 54.938044 | 1 × 54.938044 = 54.938044 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 54.938044 g/mol + 22.98976928 g/mol + 63.996 g/mol = 141.924 g/mol
Unit conversion
![0.14192 kg/mol (kilograms per mole)](../image_source/8a366dad9f929086015dfc0a5a8303f7.png)
0.14192 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/b6e86a2bd17b5079c5b9cf047ccb96a3.png)
≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.73 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/69d7651acbb536b41b7f1728213a8e61.png)
≈ 0.73 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/cf1564608be8534ff8eb82630066f4f1.png)
≈ 2.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.4×10^-22 grams | 2.4×10^-25 kg (kilograms) | 142 u (unified atomic mass units) | 142 Da (daltons)](../image_source/d0d10b819ca2e355c1865598a50bcec2.png)
Mass of a molecule m from m = M/N_A: | 2.4×10^-22 grams | 2.4×10^-25 kg (kilograms) | 142 u (unified atomic mass units) | 142 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 142](../image_source/082bdf4e04b1fb5aced6de31cf178dd1.png)
Relative molecular mass M_r from M_r = M_u/M: | 142