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molar mass of ytterbium(II) fluoride

Input interpretation

ytterbium(II) fluoride | molar mass
ytterbium(II) fluoride | molar mass

Result

Find the molar mass, M, for ytterbium(II) fluoride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: YbF_2 Use the chemical formula, YbF_2, to count the number of atoms, N_i, for each element:  | N_i  F (fluorine) | 2  Yb (ytterbium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  F (fluorine) | 2 | 18.998403163  Yb (ytterbium) | 1 | 173.045 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326  Yb (ytterbium) | 1 | 173.045 | 1 × 173.045 = 173.045  M = 37.996806326 g/mol + 173.045 g/mol = 211.042 g/mol
Find the molar mass, M, for ytterbium(II) fluoride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: YbF_2 Use the chemical formula, YbF_2, to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 2 Yb (ytterbium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 2 | 18.998403163 Yb (ytterbium) | 1 | 173.045 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 Yb (ytterbium) | 1 | 173.045 | 1 × 173.045 = 173.045 M = 37.996806326 g/mol + 173.045 g/mol = 211.042 g/mol

Unit conversion

0.211042 kg/mol (kilograms per mole)
0.211042 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.29 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.29 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 3.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 3.6 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 3.5×10^-22 grams  | 3.5×10^-25 kg (kilograms)  | 211 u (unified atomic mass units)  | 211 Da (daltons)
Mass of a molecule m from m = M/N_A: | 3.5×10^-22 grams | 3.5×10^-25 kg (kilograms) | 211 u (unified atomic mass units) | 211 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 211
Relative molecular mass M_r from M_r = M_u/M: | 211