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molar mass of 3,5-bis(trifluoromethyl)hydrocinnamic acid

Input interpretation

3, 5-bis(trifluoromethyl)hydrocinnamic acid | molar mass
3, 5-bis(trifluoromethyl)hydrocinnamic acid | molar mass

Result

Find the molar mass, M, for 3, 5-bis(trifluoromethyl)hydrocinnamic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_11H_8F_6O_2 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  F (fluorine) | 6  C (carbon) | 11  O (oxygen) | 2  H (hydrogen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  F (fluorine) | 6 | 18.998403163  C (carbon) | 11 | 12.011  O (oxygen) | 2 | 15.999  H (hydrogen) | 8 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978  C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121  O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998  H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064  M = 113.990418978 g/mol + 132.121 g/mol + 31.998 g/mol + 8.064 g/mol = 286.173 g/mol
Find the molar mass, M, for 3, 5-bis(trifluoromethyl)hydrocinnamic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_11H_8F_6O_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 6 C (carbon) | 11 O (oxygen) | 2 H (hydrogen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 6 | 18.998403163 C (carbon) | 11 | 12.011 O (oxygen) | 2 | 15.999 H (hydrogen) | 8 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 M = 113.990418978 g/mol + 132.121 g/mol + 31.998 g/mol + 8.064 g/mol = 286.173 g/mol

Unit conversion

0.2862 kg/mol (kilograms per mole)
0.2862 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 4.8×10^-22 grams  | 4.8×10^-25 kg (kilograms)  | 286 u (unified atomic mass units)  | 286 Da (daltons)
Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 286 u (unified atomic mass units) | 286 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 286
Relative molecular mass M_r from M_r = M_u/M: | 286