Input interpretation
![thallium(III) perchlorate hydrate | molar mass](../image_source/d25b2a75f3992beb10664e9ebb9238fc.png)
thallium(III) perchlorate hydrate | molar mass
Result
![Find the molar mass, M, for thallium(III) perchlorate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Tl(ClO_4)_3·xH_2O Use the chemical formula, Tl(ClO_4)_3·xH_2O, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 H (hydrogen) | 2 O (oxygen) | 13 Tl (thallium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 H (hydrogen) | 2 | 1.008 O (oxygen) | 13 | 15.999 Tl (thallium) | 1 | 204.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 13 | 15.999 | 13 × 15.999 = 207.987 Tl (thallium) | 1 | 204.38 | 1 × 204.38 = 204.38 M = 106.35 g/mol + 2.016 g/mol + 207.987 g/mol + 204.38 g/mol = 520.73 g/mol](../image_source/1649861c94e8e9ccaa91dce65f04790b.png)
Find the molar mass, M, for thallium(III) perchlorate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Tl(ClO_4)_3·xH_2O Use the chemical formula, Tl(ClO_4)_3·xH_2O, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 H (hydrogen) | 2 O (oxygen) | 13 Tl (thallium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 H (hydrogen) | 2 | 1.008 O (oxygen) | 13 | 15.999 Tl (thallium) | 1 | 204.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 13 | 15.999 | 13 × 15.999 = 207.987 Tl (thallium) | 1 | 204.38 | 1 × 204.38 = 204.38 M = 106.35 g/mol + 2.016 g/mol + 207.987 g/mol + 204.38 g/mol = 520.73 g/mol
Unit conversion
![0.5207 kg/mol (kilograms per mole)](../image_source/e7899d229efb910032a1288e82f13ef6.png)
0.5207 kg/mol (kilograms per mole)
Comparisons
![≈ 0.72 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/5dbefc2548a102474b1fab5a964c5451.png)
≈ 0.72 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.7 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/763d162df7d08a2cf0caece043867808.png)
≈ 2.7 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 8.9 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/3566efe760bac8dc0eabf5b520c1df0c.png)
≈ 8.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 8.6×10^-22 grams | 8.6×10^-25 kg (kilograms) | 521 u (unified atomic mass units) | 521 Da (daltons)](../image_source/8f97128ad422c8532b626157149bef62.png)
Mass of a molecule m from m = M/N_A: | 8.6×10^-22 grams | 8.6×10^-25 kg (kilograms) | 521 u (unified atomic mass units) | 521 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 521](../image_source/c5c39ae0b4cbc90599620feca1b6d826.png)
Relative molecular mass M_r from M_r = M_u/M: | 521