Input interpretation
![4-fluoro-1-methyl-2-nitrobenzene | molar mass](../image_source/b8266d4016a96709547f912390586279.png)
4-fluoro-1-methyl-2-nitrobenzene | molar mass
Result
![Find the molar mass, M, for 4-fluoro-1-methyl-2-nitrobenzene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3C_6H_3(NO_2)F Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 7 F (fluorine) | 1 H (hydrogen) | 6 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 7 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 6 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 84.077 g/mol + 18.998403163 g/mol + 6.048 g/mol + 14.007 g/mol + 31.998 g/mol = 155.128 g/mol](../image_source/157ba84e23cd4a788de288428da49422.png)
Find the molar mass, M, for 4-fluoro-1-methyl-2-nitrobenzene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3C_6H_3(NO_2)F Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 7 F (fluorine) | 1 H (hydrogen) | 6 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 7 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 6 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 84.077 g/mol + 18.998403163 g/mol + 6.048 g/mol + 14.007 g/mol + 31.998 g/mol = 155.128 g/mol
Unit conversion
![0.15513 kg/mol (kilograms per mole)](../image_source/8f2ce5c4f6e5bb69a4feba31688322d8.png)
0.15513 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.22 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/e99427bef5875ea5b4f513db4e555980.png)
≈ ( 0.22 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.8 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/cb4f83454941aad691b43d093fdb4053.png)
≈ 0.8 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/150db17553a5b53a1be910161b3bdd19.png)
≈ 2.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.6×10^-22 grams | 2.6×10^-25 kg (kilograms) | 155 u (unified atomic mass units) | 155 Da (daltons)](../image_source/8ea830ead77b4002e66a5e29b9b2e524.png)
Mass of a molecule m from m = M/N_A: | 2.6×10^-22 grams | 2.6×10^-25 kg (kilograms) | 155 u (unified atomic mass units) | 155 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 155](../image_source/67ff3e6ae727e1eb00135e0234126679.png)
Relative molecular mass M_r from M_r = M_u/M: | 155