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arsenic pentafluoride

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arsenic pentafluoride
arsenic pentafluoride

Chemical names and formulas

formula | AsF_5 name | arsenic pentafluoride IUPAC name | pentafluoroarsorane alternate names | arsenic pentfluoride | arsenic(V) fluoride | arsorane, pentafluoro- | pentafluoridoarsenic mass fractions | As (arsenic) 44.1% | F (fluorine) 55.9%
formula | AsF_5 name | arsenic pentafluoride IUPAC name | pentafluoroarsorane alternate names | arsenic pentfluoride | arsenic(V) fluoride | arsorane, pentafluoro- | pentafluoridoarsenic mass fractions | As (arsenic) 44.1% | F (fluorine) 55.9%

Lewis structure

Draw the Lewis structure of arsenic pentafluoride. Start by drawing the overall structure of the molecule:  Count the total valence electrons of the arsenic (n_As, val = 5) and fluorine (n_F, val = 7) atoms: n_As, val + 5 n_F, val = 40 Calculate the number of electrons needed to completely fill the valence shells for arsenic (n_As, full = 8) and fluorine (n_F, full = 8): n_As, full + 5 n_F, full = 48 Subtracting these two numbers shows that 48 - 40 = 8 bonding electrons are needed, which are already accounted for in the structure. Note that the valence shell of arsenic has been expanded to 5 bonds. After accounting for the expanded valence, there are 5 bonds and hence 10 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 40 - 10 = 30 electrons left to draw: Answer: |   |
Draw the Lewis structure of arsenic pentafluoride. Start by drawing the overall structure of the molecule: Count the total valence electrons of the arsenic (n_As, val = 5) and fluorine (n_F, val = 7) atoms: n_As, val + 5 n_F, val = 40 Calculate the number of electrons needed to completely fill the valence shells for arsenic (n_As, full = 8) and fluorine (n_F, full = 8): n_As, full + 5 n_F, full = 48 Subtracting these two numbers shows that 48 - 40 = 8 bonding electrons are needed, which are already accounted for in the structure. Note that the valence shell of arsenic has been expanded to 5 bonds. After accounting for the expanded valence, there are 5 bonds and hence 10 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 40 - 10 = 30 electrons left to draw: Answer: | |

Basic properties

molar mass | 169.91361 g/mol phase | gas (at STP) melting point | -0.4 °C boiling point | 3 °C density | 0.006945 g/cm^3 (at 20 °C)
molar mass | 169.91361 g/mol phase | gas (at STP) melting point | -0.4 °C boiling point | 3 °C density | 0.006945 g/cm^3 (at 20 °C)

Units

Gas properties (at STP)

density | 0.006945 g/cm^3 (at 20 °C) molar volume | 24470 cm^3/mol
density | 0.006945 g/cm^3 (at 20 °C) molar volume | 24470 cm^3/mol

Units

Chemical identifiers

CAS number | 7784-36-3 PubChem CID number | 82223 SMILES identifier | F[As](F)(F)(F)F InChI identifier | InChI=1/AsF5/c2-1(3, 4, 5)6 EU number | 232-061-6 Gmelin number | 2496
CAS number | 7784-36-3 PubChem CID number | 82223 SMILES identifier | F[As](F)(F)(F)F InChI identifier | InChI=1/AsF5/c2-1(3, 4, 5)6 EU number | 232-061-6 Gmelin number | 2496

NFPA label

NFPA label
NFPA label
NFPA health rating | 4 NFPA fire rating | 0 NFPA reactivity rating | 1
NFPA health rating | 4 NFPA fire rating | 0 NFPA reactivity rating | 1