Input interpretation
oxygen + 1, 3-butadiene ⟶ water + carbon dioxide
Balanced equation
Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 = c_3 + 2 c_4 C: | 4 c_2 = c_4 H: | 6 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 11/2 c_2 = 1 c_3 = 3 c_4 = 4 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 11 c_2 = 2 c_3 = 6 c_4 = 8 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 11 + 2 ⟶ 6 + 8
Structures
+ ⟶ +
Names
oxygen + 1, 3-butadiene ⟶ water + carbon dioxide
Reaction thermodynamics
Enthalpy
| oxygen | 1, 3-butadiene | water | carbon dioxide molecular enthalpy | 0 kJ/mol | -13.6 kJ/mol | -285.8 kJ/mol | -393.5 kJ/mol total enthalpy | 0 kJ/mol | -27.2 kJ/mol | -1715 kJ/mol | -3148 kJ/mol | H_initial = -27.2 kJ/mol | | H_final = -4863 kJ/mol | ΔH_rxn^0 | -4863 kJ/mol - -27.2 kJ/mol = -4836 kJ/mol (exothermic) | | |
Chemical names and formulas
| oxygen | 1, 3-butadiene | water | carbon dioxide Hill formula | O_2 | C_4H_6 | H_2O | CO_2 name | oxygen | 1, 3-butadiene | water | carbon dioxide IUPAC name | molecular oxygen | buta-1, 3-diene | water | carbon dioxide