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![9, 9-didodecylfluorene-2, 7-diboronic acid | molar mass](../image_source/4268be5aa8a4151eb868c7f59a43f9fe.png)
9, 9-didodecylfluorene-2, 7-diboronic acid | molar mass
Result
![Find the molar mass, M, for 9, 9-didodecylfluorene-2, 7-diboronic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_37H_60B_2O_4 Use the chemical formula, C_37H_60B_2O_4, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 37 B (boron) | 2 O (oxygen) | 4 H (hydrogen) | 60 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 37 | 12.011 B (boron) | 2 | 10.81 O (oxygen) | 4 | 15.999 H (hydrogen) | 60 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 37 | 12.011 | 37 × 12.011 = 444.407 B (boron) | 2 | 10.81 | 2 × 10.81 = 21.62 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 H (hydrogen) | 60 | 1.008 | 60 × 1.008 = 60.480 M = 444.407 g/mol + 21.62 g/mol + 63.996 g/mol + 60.480 g/mol = 590.50 g/mol](../image_source/6b438c246188c4ab0090c1e8b90a05c9.png)
Find the molar mass, M, for 9, 9-didodecylfluorene-2, 7-diboronic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_37H_60B_2O_4 Use the chemical formula, C_37H_60B_2O_4, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 37 B (boron) | 2 O (oxygen) | 4 H (hydrogen) | 60 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 37 | 12.011 B (boron) | 2 | 10.81 O (oxygen) | 4 | 15.999 H (hydrogen) | 60 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 37 | 12.011 | 37 × 12.011 = 444.407 B (boron) | 2 | 10.81 | 2 × 10.81 = 21.62 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 H (hydrogen) | 60 | 1.008 | 60 × 1.008 = 60.480 M = 444.407 g/mol + 21.62 g/mol + 63.996 g/mol + 60.480 g/mol = 590.50 g/mol