Input interpretation
1-(2, 3, 4, 5, 6-pentafluorophenyl)-1-propanol | molar mass
Result
Find the molar mass, M, for 1-(2, 3, 4, 5, 6-pentafluorophenyl)-1-propanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6F_5CHOHCH_2CH_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 F (fluorine) | 5 H (hydrogen) | 7 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 F (fluorine) | 5 | 18.998403163 H (hydrogen) | 7 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 F (fluorine) | 5 | 18.998403163 | 5 × 18.998403163 = 94.992015815 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 108.099 g/mol + 94.992015815 g/mol + 7.056 g/mol + 15.999 g/mol = 226.146 g/mol
Unit conversion
0.22615 kg/mol (kilograms per mole)
Comparisons
≈ 0.31 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.8×10^-22 grams | 3.8×10^-25 kg (kilograms) | 226 u (unified atomic mass units) | 226 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 226