Input interpretation
nitric acid + ferrous sulfide ⟶ water + mixed sulfur + nitrogen dioxide + ferric nitrate
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Fe and S: H: | c_1 = 2 c_3 N: | c_1 = c_5 + 3 c_6 O: | 3 c_1 = c_3 + 2 c_5 + 9 c_6 Fe: | c_2 = c_6 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 1 c_3 = 3 c_4 = 1 c_5 = 3 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + ⟶ 3 + + 3 +
Structures
+ ⟶ + + +
Names
nitric acid + ferrous sulfide ⟶ water + mixed sulfur + nitrogen dioxide + ferric nitrate
Chemical names and formulas
| nitric acid | ferrous sulfide | water | mixed sulfur | nitrogen dioxide | ferric nitrate Hill formula | HNO_3 | FeS | H_2O | S | NO_2 | FeN_3O_9 name | nitric acid | ferrous sulfide | water | mixed sulfur | nitrogen dioxide | ferric nitrate IUPAC name | nitric acid | | water | sulfur | Nitrogen dioxide | iron(+3) cation trinitrate