Input interpretation
1-chloro-5-triethylsilyl-1-pentyne | molar mass
Result
Find the molar mass, M, for 1-chloro-5-triethylsilyl-1-pentyne: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_11H_21ClSi Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 11 Cl (chlorine) | 1 H (hydrogen) | 21 Si (silicon) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 11 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 21 | 1.008 Si (silicon) | 1 | 28.085 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 21 | 1.008 | 21 × 1.008 = 21.168 Si (silicon) | 1 | 28.085 | 1 × 28.085 = 28.085 M = 132.121 g/mol + 35.45 g/mol + 21.168 g/mol + 28.085 g/mol = 216.82 g/mol
Unit conversion
0.2168 kg/mol (kilograms per mole)
Comparisons
≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 217 u (unified atomic mass units) | 217 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 217