Input interpretation
aluminium, compound with barium (4:1) | molar mass
Result
Find the molar mass, M, for aluminium, compound with barium (4:1): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BaAl_4 Use the chemical formula, BaAl_4, to count the number of atoms, N_i, for each element: | N_i Al (aluminum) | 4 Ba (barium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Al (aluminum) | 4 | 26.9815385 Ba (barium) | 1 | 137.327 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Al (aluminum) | 4 | 26.9815385 | 4 × 26.9815385 = 107.9261540 Ba (barium) | 1 | 137.327 | 1 × 137.327 = 137.327 M = 107.9261540 g/mol + 137.327 g/mol = 245.253 g/mol
Unit conversion
0.245253 kg/mol (kilograms per mole)
Comparisons
≈ 0.34 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 4.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 4.1×10^-22 grams | 4.1×10^-25 kg (kilograms) | 245 u (unified atomic mass units) | 245 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 245