Input interpretation
niobium boride | molar mass
Result
Find the molar mass, M, for niobium boride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NbB Use the chemical formula to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 Nb (niobium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 Nb (niobium) | 1 | 92.90637 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 Nb (niobium) | 1 | 92.90637 | 1 × 92.90637 = 92.90637 M = 10.81 g/mol + 92.90637 g/mol = 103.72 g/mol
Unit conversion
0.10372 kg/mol (kilograms per mole)
Comparisons
≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.53 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 104 u (unified atomic mass units) | 104 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 104