Input interpretation
[bis(trifluoroacetoxy)iodo]benzene | molar mass
Result
Find the molar mass, M, for [bis(trifluoroacetoxy)iodo]benzene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (CF_3CO_2)_2IC_6H_5 Use the chemical formula, (CF_3CO_2)_2IC_6H_5, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 10 F (fluorine) | 6 H (hydrogen) | 5 I (iodine) | 1 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 10 | 12.011 F (fluorine) | 6 | 18.998403163 H (hydrogen) | 5 | 1.008 I (iodine) | 1 | 126.90447 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 120.110 g/mol + 113.990418978 g/mol + 5.040 g/mol + 126.90447 g/mol + 63.996 g/mol = 430.041 g/mol
Unit conversion
0.43004 kg/mol (kilograms per mole)
Comparisons
≈ 0.6 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 7.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 7.1×10^-22 grams | 7.1×10^-25 kg (kilograms) | 430 u (unified atomic mass units) | 430 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 430